CH 9 HW key - Chapter 9 1. = length/original length =...

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Chapter 9 1. ε= length/original length = (1.001-1)/1= 0.001cm/cm= 0.1% 2. A= 50mm²= 0.5cm², F= 10000N σ = F/A = 10000/0.5= 20,000 N/cm² 3. E= 12GPa, σ= 60MPa E = ∆σ / ∆ε -> ε= ∆σ /E=( 60*10^6)/(12*10^9)= 0.005= 0.5% 4. ε=6%= 0.06cm/cm, l(original)= 10cm ε= length/original length= Δl/10=0.06 -> Δl=0.6 cm (tendon elongates 0.6cm) 5. σ= 10MPa, ε=0.10%=0.001 E = ∆σ / ∆ε = (10*10^6)/0.001=10* 10^9= 10GPa 6. E=20GPa, r=1cm=0.01m, l=3cm, lc=3.003cm, ε= length/original length=(3-3.003)/3=0.003/3=0.001 cm/cm E= ∆σ / ∆ε -> σ=E*ε= (20*10^9)*0.001= 20MPa A=πr²=0.0001π σ=F/A-> F=σ*A= 20M* 0.0001π=2000π= 6283.2N
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This note was uploaded on 11/17/2011 for the course KNH 381 Lectur taught by Professor Walsh during the Summer '11 term at Miami University.

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CH 9 HW key - Chapter 9 1. = length/original length =...

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