Soln Conc1 - Section 14 Solution Concentration Percent by...

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Section 14 Solution Concentration Percent by Mass e.g. 10.5 % aqueous H 2 SO 4 consider a 100.0 g sample: 10.5 g H 2 SO 4 and 89.5 g H 2 O
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Mole Fraction, X The ratio of the number of moles (or molecules) of one component to the total number of moles (or molecules) of all components in a solution For a two component solution: X solute = no. moles solute no. moles solute + no. moles solvent X solvent = no. moles solvent no. moles solute + no. moles solvent
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Calculate the mole fractions of the two component solution that contains 30.5 g glycerin (C 3 H 8 O 3 ) and 22.1 g H 2 O. X glyc = no. moles C 3 H 8 O 3 = 0.331 mol = 0.212 no. moles C 3 H 8 O 3 + no. moles H 2 O 0.331 mol + 1.23 mol X water = no. moles H 2 O = 1.23 mol = 0.788 no. moles C 3 H 8 O 3 + no. moles H 2 O 0.331 mol + 1.23 mol Note: Sum of all mole fractions = 1, here… 0.212 + .788 = 1.00 moles glycerin, 30.5 g C 3 H 8 O 3 x 1 mol = 0.331 mol C 3 H 8 O 3 92.1 g moles water, 22.1 g H 2 O x 1 mol = 1.23 mol H 2 O 18.0 g
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Soln Conc1 - Section 14 Solution Concentration Percent by...

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