Physics 1 Problem Solutions 40

# Physics 1 Problem Solutions 40 - 36 Chapt. 4 Two- and...

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Unformatted text preview: 36 Chapt. 4 Two- and Three-Dimensional Kinematics 11. The ratio of the maximum height formula (for projectile motion near the Earth’s surface, neglecting air drag, and measuring from the launch height) to the horizontal range formula (for projectile motion near the Earth’s surface and neglecting air drag) is and its value for the maximum range is . a) y max x range = 1 4 tan θ ; 1 4 b) y max x range = 1 4 tan θ ; 1 c) y max x range = tan θ ; 1 d) y max x range = tan θ ; 1 4 e) y max x range = 1 4 tan θ ; ∞ 004 qmult 00300 1 4 5 easy deducto-memory: relative motion explained 12. “Let’s play Jeopardy ! For \$100, the answer is: Motion of something with respect to something else. To be a bit more explicit, say you have two objects. The relative displacement of object 2 from object 1 is defined to be vector r = vector r 2 − vector r 1 . From this definition, the relative velocity and acceleration follow from differentiation: vectorv = vectorv 2 − vectorv 1 and vectora = vectora...
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## This note was uploaded on 11/16/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.

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