Physics 1 Problem Solutions 76

Physics 1 Problem Solutions 76 - 72 Chapt. 6 Newtons Laws...

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Unformatted text preview: 72 Chapt. 6 Newtons Laws and Dynamics II VELOCITY (radians per second) of the Earth at the equator. What values does he get? HINT: Waldo does remember about the circumference of a circle. b) Now Waldo calculates the magnitude of centripetal acceleration for a body on the equator. What does he find? c) The sagacious swine now reflects on inertial frames. For most purposes the Earths surface is a pretty good inertial frame. But the Earth is rotating, and so its not exactly an inertial frame. The fixed stars (as they are called for historical reasons) define a more inertial frame. Say we takeWaldo says to himself vectora in Newtons 2nd law vector F net = mvectora and decompose it (as nothing forbids us to do) into acceleration relative to the rotating frame of equatorial Ecuador (i.e., vectora ) and centripetal acceleration ( vectora c = a c r , where r is a radially outward pointing unit vector) which is the acceleration of the rotating frame. We obtain vectora...
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This note was uploaded on 11/16/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.

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