Physics 1 Problem Solutions 127

Physics 1 Problem Solutions 127 - Chapt. 14 Gravity 123 at...

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Unformatted text preview: Chapt. 14 Gravity 123 at some fiducial point inside of it (its center of mass usually being the best choice) and its mass. This case follows directly from: a) Newton’s 1st law. b) Newton’s 2nd law. c) Newton’s 3rd law. d) cases 2 and 3. e) case 3. 014 qmult 00200 1 1 1 easy memory: fiducial gravitational force 8. A fiducial gravitational force is the force between two non-overlapping spherically symmetric objects each of mass 1 kg with the center-to-center distance one meter. The magnitude of this force is: a) 1. b) 1/2. c) 6 . 67428 × 10 11 . d) 1 . 67 × 10 − 11 . e) 6 . 67428 × 10 − 11 . 014 qmult 00210 1 3 3 easy math: gravity force calculation 9. Using Newton’s gravitation law vector F 12 = − Gm 1 m 2 r 2 ˆ r 12 ( G = 6 . 67428(67) × 10 − 11 N m 2 /kg 2 : e.g., NIST constants 2009may05) calculate the magnitude of the force between two 3 kg objects 3 m apart. The answer is: a) 60 . 1 × 10 − 11 ≈ 12 × 10 − 11 lb. b) 20 . × 10 − 11 ≈ 4 × 10 − 11 lb.lb....
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This note was uploaded on 11/16/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.

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