{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Physics 1 Problem Solutions 134

# Physics 1 Problem Solutions 134 - 130 Chapt 14 Gravity e(i...

This preview shows page 1. Sign up to view the full content.

130 Chapt. 14 Gravity e) (i) r = parenleftBig P GM parenrightBig 2 / 3 (ii) r = 12742 km. Full-Answer Problems 014 qfull 00100 1 3 0 easy math: calculate g gravitational acceleration 1. Calculate the gravitational acceleration g for the Earth’s surface given G = 6 . 67428(67) × 10 11 MKS units, Earth mass M E = 5 . 9736 × 10 24 kg, and mean Earth radius R E = 6 . 37101 × 10 6 m (Wikipedia: 2007sep25). What is the percentage difference from the fiducial g fid = 9 . 80 m / s 2 that is commonly used. 014 qfull 00300 3 5 0 tough thinking: grav potential in spherical symmetry 2. Given that the gravitational field of a uniform density sphere of mass M and radius R is vectorg = GM ( ˆ r ) 1 r 2 r R ; 1 R 2 r R r R , what is the expression for the gravitational potential energy per unit mass V (usually called the gravitational potential)? Take the zero of the gravitational potential to be at infinity. HINT: Watch those constants of integration. 014 qfull 00660 3 5 0 tough thinking: Kepler’s 3rd law Extra keywords: planetary orbital speeds 3. Obtain the following circular orbit results.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern