Physics 1 Problem Solutions 180

Physics 1 Problem - 176 Chapt 22 Electric Charge where k = 8 98755179 × 10 9 Nm 2 C 2 G = 6 67428(67 × 10 − 11 in MKS units q stands for charge

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Unformatted text preview: 176 Chapt. 22 Electric Charge where k = 8 . 98755179 × 10 9 Nm 2 / C 2 , G = 6 . 67428(67) × 10 − 11 in MKS units, q stands for charge, m for mass, 1 and 2 for particles 1 and 2, and r is the distance between the particles. The mass of electrons is 9 . 1093826 × 10 − 31 kg and their electric charge is 1 . 60217653 × 10 − 19 C. Approximately, what is the ratio of the magnitude of gravitational force to the magnitude of the electrical force between two electrons (i.e., F G /F C ) for any distance r ? a) 1. b) 10. c) 3 × 10 − 43 . d) 3 × 10 43 . e) 10 − 19 . 022 qmult 00800 1 1 3 easy memory: polarization 25. Charge separation in a object is called: a) rasterization. b) pasteurization. c) polarization. d) north polarization. e) miniaturization. 022 qmult 00910 1 1 3 easy memory: two-ball induction charging 1 26. Two uncharged conducting balls A and B are mounted on insulating stands. The balls are touching. A positively charged rod is brought from infinity to near B, but not near A. The ballstouching....
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This note was uploaded on 11/16/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.

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