This preview shows page 1. Sign up to view the full content.
Unformatted text preview: Chapt. 27 Currents and Resistance 211 A to B. Using the two results find the formula for ratio R . What does one actually need to evaluate the formula? h) Say one had the special case of exact cross sectional symmetry along an axis: i.e., the conductor cross section was constant along the axis and the Efield was uniform everywhere in the conductor and its direction was parallel to the axis of symmetry. In this case, there is no guide charge. The cross sectional area is A and the conductor length is . 027 qfull 00410 2 3 0 moderate math: power integrated for heater 6. A 1250 W radiant heater operates with a potential difference across it of 115 V. a) What is the current in the heater? b) What is the resistance R of the heater coil? c) How much energy (in MKS units) does the heater absorb and emit (its the same amount) in a time t = 1 hour? d) Now say that due to a defect the resistor starts to increase in resistance from its proper value R calculated in part (b). The resistance increases according to the expressioncalculated in part (b)....
View
Full
Document
This note was uploaded on 11/16/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.
 Fall '06
 Buchler
 Physics, Current, Resistance

Click to edit the document details