104EX2prac2'_ans

104EX2prac2'_ans - point of maximum separation? [Ag + ] =...

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6.( 6 pts) (a) A mixture is made up which is 0.100 M in both Ag + and Cu + ion. If the K sp of AgCl is 1.8 x 10 -10 and that of CuCl is 1.7 x 10 -7 , what concentration of Cl - ion achieves the maximum separation of the two cations; i.e, the most soluble ion remains in solution at 0.100M? [Ag + ] [ Cl - ] = 1.8 x 10 -10 and [Cu + ] [ Cl - ] = 1.7 x 10 -7 Use the one with largest Ksp to find [ Cl - ] at maximum separation. [ Cl - ] = (1.7 x 10 -7 / .1 ) = 1.7 x 10 -6 M ( 4 pts) ( b) What is the concentration of least soluble ion remaining in solution at the
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Unformatted text preview: point of maximum separation? [Ag + ] = 1.8 x 10-10 / [ Cl-] = 1.8 x 10-10 / 1.7 x 10-6 = 1.1 x 10-4 M [Cu + ] = 0.100M [ Cl-] = 1.7 x 10-6 M so 1.7 x 10-6 M is ans. 7. a) (2 pts) Circle (underline) the strongest Acid: H 2 Se GeH 4 AsH 3 H 2 S SiH 3 b) (2 pts) Circle the base with the highest pK b : ClO-BrO-BrO 2- IO 4-ClO 2-c) (2 pts) Circle the acid with the lowest pK a : H 3 PO 4 H 3 AsO 3 H 3 AsO 4 H 2 CO 3 H 2 SO 4 d) (2 pts) Circle the acid with the highest pK a : HClO 3 HClO 2 HBrO 3 HBrO HFO...
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This note was uploaded on 11/14/2011 for the course CHEM 104 taught by Professor Salame during the Fall '08 term at CUNY City.

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104EX2prac2'_ans - point of maximum separation? [Ag + ] =...

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