madrid (tmm2353) – HW #12 – Antoniewicz – (56445)
1
This printout should have 30 questions.
Multiplechoice questions may continue on
the next column or page – fnd all choices
beFore answering.
001 (part 1 of 7) 3.0 points
A spacecraFt is observed to be at loca
tion
a
200 m
,
300 m
,
−
400 m
A
relative to an
origin located on a nearby asteroid, and
5 s later it is observed to be at location
a
475 m
,
75 m
,
−
700 m
A
.
±ind the average ve
locity oF the spacecraFt, ¯
v
=
a
v
x
, v
y
, v
z
A
.
What is
v
x
in m/s?
Correct answer: 55 m
/
s.
Explanation:
The average velocity oF the spacecraFt is
calculated by fnding the change oF position
over a change in time:
¯
v
=
Vr
f
−
i
Δ
t
.
Because
is a vector, the average velocity will
also be a vector and each component must be
calculated separately.
±or ¯
v
x
the value becomes:
¯
v
x
=
v
2
x
−
v
1
x
Δ
t
=
(475 m)
−
(200 m)
(5 s)
=
55 m
/
s
002 (part 2 of 7) 3.0 points
What is
v
y
in m/s?
Correct answer:
−
45 m
/
s.
Explanation:
The average velocity oF the spacecraFt is
calculated by fnding the change oF position
over a change in time:
¯
v
=
f
−
i
Δ
t
.
Because
is a vector, the average velocity will
also be a vector and each component must be
calculated separately.
±or ¯
v
y
the value becomes:
¯
v
y
=
v
2
y
−
v
1
y
Δ
t
=
(75 m)
−
(300 m)
(5 s)
=
−
45 m
/
s
003 (part 3 of 7) 2.0 points
What is
v
z
in m/s?
Correct answer:
−
60 m
/
s.
Explanation:
The average velocity oF the spacecraFt is
calculated by fnding the change oF position
over a change in time:
¯
v
=
f
−
i
Δ
t
.
Because
is a vector, the average velocity will
also be a vector and each component must be
calculated separately.
±or ¯
v
z
the value becomes:
¯
v
z
=
v
2
z
−
v
1
z
Δ
t
=
(
−
700 m)
−
(
−
400 m)
(5 s)
=
−
60 m
/
s
004 (part 4 of 7) 4.0 points
What is

Vv

in m/s?
Correct answer: 93
.
0054 m
/
s.
Explanation:
The magnitude is calculated by:


=
r
v
2
x
+
v
2
y
+
v
2
z
=
r
(55 m
/
s)
2
+ (
−
45 m
/
s)
2
+ (
−
60 m
/
s)
2
=
93
.
0054 m
/
s
005 (part 5 of 7) 3.0 points
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Documentmadrid (tmm2353) – HW #12 – Antoniewicz – (56445)
2
Find the unit vector in the direction of the
velocity of the spacecraft, ˆ
v
=
a
ˆ
v
x
,
ˆ
v
y
,
ˆ
v
z
A
.
What is ˆ
v
x
?
Correct answer: 0
.
591364.
Explanation:
The unit vector for a vector is given as :
ˆ
v
=
a
ˆ
v
x
,
ˆ
v
y
,
ˆ
v
z
A
=
a
v
x
, v
y
, v
z
A

Vv

For example:
ˆ
v
x
=
v
x


=
55 m
/
s
93
.
0054 m
/
s
=
0
.
591364
006 (part 6 of 7) 3.0 points
What is ˆ
v
y
?
Correct answer:
−
0
.
483843.
Explanation:
The unit vector for a vector is given as :
ˆ
v
=
a
ˆ
v
x
,
ˆ
v
y
,
ˆ
v
z
A
=
a
v
x
, v
y
, v
z
A


For example:
ˆ
v
y
=
v
y


=
−
45 m
/
s
93
.
0054 m
/
s
=
−
0
.
483843
007 (part 7 of 7) 2.0 points
What is ˆ
v
z
?
Correct answer:
−
0
.
645124.
Explanation:
The unit vector for a vector is given as :
ˆ
v
=
a
ˆ
v
x
,
ˆ
v
y
,
ˆ
v
z
A
=
a
v
x
, v
y
, v
z
A


For example:
ˆ
v
z
=
v
z


=
−
60 m
/
s
93
.
0054 m
/
s
=
−
0
.
645124
008 (part 1 of 7) 3.0 points
Here are the positions at three di±erent
times for a bee in ²ight (a bee’s top speed is
about 7
m/s .
This is the end of the preview.
Sign up
to
access the rest of the document.
 Fall '08
 Turner
 Velocity, Trigraph, Correct Answer, 2007 albums

Click to edit the document details