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IRWIN 9e 9_18

# IRWIN 9e 9_18 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 9.18 Given the iiem-‘ui'k in Fig. PL}. 1H. shuw ihiii 1lie pun-er supplied by the suLIi'ees is equal in line pus-er zihsurhed h}; the passive elements. if}? H Ilia n I, . gﬁs 5 4n 5 :45“: Figure P918 SOLUTION: ‘ 1.35 L4/‘7674 I: : €445 .. \7,’ 6 L553. ¥232.[:1~/.%§° w.- ii 1'1 Chapter 9: Steady — State Power Analysis Problem 9.18 ‘ 2 Irwin, Basic Engipeering Circuit Analysis, 9/E .. VI . F13 ' 1: W<&v— 94,) (’1S , (Lama) Vau<4+ \$6109 2. PI: .: 5- N va : V51:- ch<9V—®£) 2.- R5 = 60%?) m(4s'°’u¥.4§°) 9— R3 = 1.2L: N Fm: If"? z (1-83)"(4) 2. 2. KM.“ :. 6‘? N 0W PW ; PM PIS T RE .: P44» 5.96 +1.29: 6.4 6"}N ; Problem 9.18 Chapter 9: Steady — State Power Analysis ...
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