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IRWIN 9e 9_80

IRWIN 9e 9_80 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis, 9/E 9.3a Given the circuit in Fig. P912813, find the complcx pcwcr supplied by Line source and the scurcc power faclcr. If f = fill} Hz, find 115(1). 30 kW 20 EVA 10 kW [LE CI. 0.8 leading lagging lagging Figure P930 SOLUTION: ’1 + aokw 20kVA I 10kw “.8 0.9 0.8 480m V m leaning lagging lagging I5 I i 7; Pi _. 30 k ________.,.. _ VLQPF.) 480(0'8) 1"; 78'15 Akmg i]: 12MB LCDJ"(O-5) 1,: 78.13 Lemar" Am: I : pic ; /8L Vb Pp» (480)09) Ia: (N6? A 11mg fa 1 Lil'érlt (EMTQQO Awmg 430E V rms Chapter 9: Steady — State Power Analysis Problem 9.80 2 Irwin. Basic Engineering CircuitAnalysis, 9/E 1}) : P5 _ 10k "_____—————-— Vt ”3 (4Bo)(o.8) 15'; 46'09 gm "’(0-8) I}; °?6’O(1’ L’36'81 Admg f: 131’ ELTEB .— 1 3 78.13 L36-85F0-I‘ 9I.e#L—as‘.gq°+ 926.04L-35.31° i: L215: [543% 4mg u.— VS :1: (o-t-r 30.2) +480 LO° h vs = LIAIA‘S’ Lé‘I8°)(0~l+j0’2-)—r480[‘o° Problem 9.80 Chapter 9: Steady — State Power Analysis ...
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