chapter8 - of N, so it is not surprising that the same...

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Homework Chapter 8 4 V 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 3 4 s 2 20 (a) 18 electrons (b) 10 electrons (c) 1 electron (d) none; when l = 0, m l can only have a value of 0 22 P [Ne] 3 s 3 p ↑↓ n = 3, l = 0, m l = 0, m s = + 1 / 2 n = 3, l = 0, m l = 0, m s = – 1 / 2 n = 3, l = 1, m l = –1, m s = + 1 / 2 n = 3, l = 1, m l = 0, m s = + 1 / 2 n = 3, l = 1, m l = +1, m s = + 1 / 2 32 (a) Al (b) Al (c) C (based on periodic trends) Si (according to experimental data) (d) Al < B < C 34 (a) F < O < S The trend is to increase to the left and down the periodic table. (b) Based on knowledge of first-order periodic trends, we would predict that S should have the largest IE of the group P, Si, S, and Se. However, recall that the O atom IE is smaller than that
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Unformatted text preview: of N, so it is not surprising that the same effect carries over into the third period. That is, the order of ionization energies is Si &lt; Se &lt; S &lt; P. (c) F &lt; O 2 &lt; N 3 These ions are isoelectronic and size increases as the number of protons in the nucleus available to attract the electrons decreases. (d) Cs &lt; Ba &lt; Sr The trend is to increase to the right and decrease down the periodic table. 44 (a) P, phosphorus (b) Be, beryllium (c) N, nitrogen (d) Tc, technetium (e) Cl, chlorine (f) Zn, zinc...
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chapter8 - of N, so it is not surprising that the same...

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