# Chapter 19 - Chapter 19 Homework 19.8 S = S[NH3(g cfw_1/2...

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Chapter 19 Homework 19.8 S º = S º[NH 3 (g)] – { 1 / 2 S º[N 2 (g)] + 3 / 2 S º[H 2 (g)]} S º = 1 mol (192.77 J/K·mol) – { 1 / 2 mol (191.56 J/K·mol) + 3 / 2 mol (130.7 J/K·mol)} S º = –99.1 J/K 19.28 G º rxn = G f º[TiCl 4 ( l )] – G f º[TiCl 2 (s)] –272.8 kJ = 1 mol (–737.2 kJ/mol) – 1 mol G f º[TiCl 2 (s)] G f º[TiCl 2 (s)] = –464.4 kJ/mol 19.32 CaSO 4 (s) CaO(s) + SO 3 (g) H º = { H f º[CaO(s)] + H f º[SO 3 (g)]} – H f º[CaSO 4 (s)] H º = {1 mol(–635.09 kJ/mol) + 1 mol(–395.77 kJ/mol)} – 1 mol(–1434.52 kJ/mol) 403.66 kJ S º = { S º[CaO(s)] + S º[SO 3 (g)]} – S º[CaSO 4 (s)] S º = {1 mol (38.2 J/K·mol) + 1 mol (256.77 J/K·mol)} – 1 mol (106.5 J/K·mol) 188.5 J/K G º = 0 = H º – T S º = 403.66 kJ – T (188.5 J/K)(1 kJ/10 3 J) T = 2141 K or greater 19.36 G º = 2 G f º[HCl(g)] – 2 G f º[HBr(g)] G º = 2 mol (–95.09 kJ/mol) – 2 mol (–53.45 kJ/mol)

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Chapter 19 - Chapter 19 Homework 19.8 S = S[NH3(g cfw_1/2...

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