chapter15 - Homework Chapter 15 15.16 (a) Comparing...

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Homework Chapter 15 15.16 (a) Comparing experiment 1 to experiment 2, [H 2 PO 4 ] remains constant, [OH ] doubles, and the rate increases by a factor of four. The reaction is second order in OH . Comparing experiment 1 to experiment 3, [OH ] is constant, [H 2 PO 4 ] triples, and the rate triples. The reaction is first order in H 2 PO 4 . Rate = k [H 2 PO 4 ][OH ] 2 (b) [] [ ] [] [ ] min 10 2 . 4 00040 . 0 0030 . 0 min / 0020 . 0 2 6 2 2 4 2 × = = = M M OH PO H Rate k (c) [] [] () [] M M M M OH k Rate PO H 0044 . 0 00033 . 0 min 10 2 . 4 min / 0020 . 0 2 1 6 2 4 2 = × = = 15.24 When three-fourths of the sample has decomposed, the fraction remaining is 1 / 4 () s t t s 580 10 4 . 2 4 1 ln 1 3 = × =
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15.34 The plot of ln[phenyl acetate] versus time is linear, so the reaction is first order in phenyl acetate. k
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This note was uploaded on 11/16/2011 for the course CHEM 1212k taught by Professor Wood during the Spring '08 term at Valdosta State University .

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chapter15 - Homework Chapter 15 15.16 (a) Comparing...

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