chapter18 - Homework Chapter 18 18.8 (a) CH3CHOHCO2H(aq) +...

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Chapter 18 18.8 (a) CH 3 CHOHCO 2 H(aq) + H 2 O( l ) ' H 3 O + (aq) + CH 3 CHOHCO 2 (aq) = 2 3 0491 . 0 500 . 0 / 1 . 112 75 . 2 CHOCO CH M L mol g g [ ][ ] [] [] [ ] [] [] [ ] [] [] [] 54 . 3 log 10 9 . 2 100 . 0 0491 . 0 10 4 . 1 100 . 0 0491 . 0 10 4 . 1 3 4 3 4 4 2 3 2 3 3 = = × = = = × + = × = + + + O H pH M O H x x x x x H CHOCO CH CHOCO CH O H K a (b) The buffer solution has a higher pH than the original lactic acid solution (pH = 2.43) because a weak base (CH 3 CHOHCO 2 ) was added to the lactic acid solution. 18.12 p K a = –log( K a ) = –log(5.6 × 10 –10 ) = 9.25 pH = p K a + log [NH 3 ] [NH 4 + ] = 9.25 + log 0.045 0.050 = 9.21 18.18 [ H 3 O + ] = 10 –pH = 10 –9.5 = 3.16 × 10 –10 M [ ][ ] [] [] [] [] [] [] + + + + = × = × = 4 3 4 3 10 10 4 3 3 8 . 1 10 16 . 3 10 6 . 5 NH NH NH NH NH NH O H K a A solution in which the NH 3
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chapter18 - Homework Chapter 18 18.8 (a) CH3CHOHCO2H(aq) +...

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