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chapter23 - = 0.28241 g/mol E b = ∆ m c 2 =(0.28241 × 10...

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Homework Chapter 23 23.13 (a) 1 1 H (d) 2 0 1 n (b) 13 27 Al (e) 102 254 No (c) 0 1 n (f) 8 16 O 23.15 (a) 9 19 F (d) 17 37 Cl (b) 27 59 Co (e) 25 55 Mn (c) 20 40 Ca (f) 1 1 H 23.19 (a) 31 67 Ga + Š1 0 e 30 67 Zn (b) 19 38 K 18 38 Ar + + 1 0 β (c) 43 99m Tc 43 99 Tc + γ (d) 25 56 Mn 26 56 Fe + Š1 0 β 23.25 15 30 P 15 1 1 H + 15 0 1 n m = [(15 × 1.00783) + (15 × 1.00867)] – 29.97832 = 0.26918 g/mol nuclei E b = ( m ) c 2 = (0.26918 × 10 –3 kg)(3.00 × 10 8 m/s) 2 = 2.42 × 10 13 J/mol nuclei = 2.42 × 10 10 kJ/mol E b n = 2.42 × 10 10 kJ/mol nuclei 30 mol nucleons/mol nuclei = 8.08 × 10 8 kJ/mol nucleons 15 31 P 15 1 1 H + 16 0 1 n m = [(15 × 1.00783) + (16 × 1.00867)] – 30.97376 = 0.28241 g/mol
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Unformatted text preview: = 0.28241 g/mol E b = ( ∆ m ) c 2 = (0.28241 × 10 –3 kg)(3.00 × 10 8 m/s) 2 = 2.54 × 10 13 J/mol nuclei = 2.54 × 10 10 kJ/mol E b n = 2.54 × 10 10 kJ/mol nuclei 31 mol nucleons/mol nuclei = 8.20 × 10 8 kJ/mol nucleons 23.37 1 4 3 2 / 1 10 21 . 1 10 73 . 5 693 . 694 . − − × = × = = y y t k t y kt ) 10 21 . 1 ( . 14 2 . 11 ln . 14 2 . 11 ln 1 4 − − × − = − = t = 1850 years old Year made = 2006 – 1850 = 156 AD...
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