chapter 7 Impulse and Momentum

chapter 7 Impulse and Momentum - so KE of heavier = 8500J =...

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chapter 7 Impulse and Momentum definition == impulse = F * t v = (xf - xi)/change in time F = ma = m (vf-vi)/t unit= F> N delta t= s J = Nsec def linear momentum P = mv impulse- momentum theorem (sum of F)*t = change in momentum = mvf - mvi ONLINE QUIZ number 5 m1= 2.2m2 8500 J released KEi = 1/2m1*v1^2 pi = pf Mvo = m1v1 + m2v2 0= -m1v1 + m2v2 m1v1=m2v2 2.2m2v1=m2v2 v2 = 2.2v1
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Unformatted text preview: so KE of heavier = 8500J = 1/2m1v2^2 + 1/2m2v2^2 8500 = 1/2 (2.2m2) (v1^2) + 1/2m2 (2.2v1)^2 COLLISION in 1D 1) Elastic collision = (KE initial) = (KE final) 2) inelastic collision= (KE initial) != (KE final) Completely inelastic = the objects stick together COLLISION IN 2D F --> Fx, Fy P --> Px, Py X: Pxi = Pxf y: Pyi = Pxf...
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