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# 6 v t c t 86 003 c t c t 86 003 t t 86

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Unformatted text preview: ⇒ 343 (t + 6) = (3 · 108) t t = 6.8600078 · 10-6 s d = 2058.0024 m So, the lightning strike really occurred a couple millimeters farther away than we had calculated the first way. Note: The difference in results is meaningless here since we can’t know the time delay or the speed of sound to as many significant digits as our answer has. Space Travel & The Speed of Light We can’t always ignore the time light takes to travel. Whenever you look into the night sky, for example, you’re really looking back into time. The stars you see are so far away that the light they emit takes years to reach us. Nearby stars are tens or hundreds light-years away. A light-year is the distance light travels in one year, almost 6 trillion miles. (Our sun is only about 8 light-minutes away). Problem: Schmedrick is on a space journey heading toward Alpha Centauri, the nearest star excluding the sun, which is about 4.3 lightyears away. Schmedrick's rocket goes a constant 0.03 c (3% of the speed of light). As he...
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## This note was uploaded on 11/17/2011 for the course PHYS 121 taught by Professor Burgeson during the Fall '11 term at BYU.

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