29.61: a) ∫ + → + = ⇒ = = ⋅ × = L d d d L d π Iv μ r dr π Iv μ dr πr Iv μ vBdr d dε . ln 2 2 2 ) (000 ε r B v b) The magnetic force is strongest at the top end, closest to the current carrying wire. Therefore, the top end, point a , is the higher potential since the force on positive charges is greatest there, leading to more positives gathering at that end. c) If the single bar was replaced by a rectangular loop, the edges parallel to the wire
This is the end of the preview. Sign up
access the rest of the document.
This homework help was uploaded on 02/03/2008 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.