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problem29_61 - 0 Iv 0 Iv d L dr 0 Iv d L dr ln d 2r 2 r 2 d...

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29.61: a) + + = = = × = L d d d L d π Iv μ r dr π Iv μ dr πr Iv μ vBdr d . ln 2 2 2 ) ( 0 0 0 ε r B v b) The magnetic force is strongest at the top end, closest to the current carrying wire. Therefore, the top end, point a , is the higher potential since the force on positive charges is greatest there, leading to more positives gathering at that end. c) If the single bar was replaced by a rectangular loop, the edges parallel to the wire
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