Exam 2-solutions - Version 217 Exam 2 mccord(51600 This print-out should have 35 questions Multiple-choice questions may continue on the next

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Version 217 – Exam 2 – mccord – (51600) 1 This print-out should have 35 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 3.0 points How many double bonds are in the compound CH 2 CHCH 2 CHCH 2 ? 1. 1 2. 3 3. 2 correct 4. 0 5. 4 Explanation: The Lewis dot structure is H C H C H C H H C H C H H 002 3.0 points How many resonance Forms are possible For the ethanoate ion? The Formula For the ethanoate ion is CH 3 COO . 1. 2 correct 2. 4 3. 1 4. 3 5. 5 Explanation: The Lewis structures are C O b b b H 3 C O C O H 3 C O b b 003 3.0 points Which oF the Following is diamagnetic? 1. O 2 2. O 2 2 correct 3. O + 2 4. O 2 Explanation: All but O 2 2 are paramagentic (possess un- paired electrons). 004 3.0 points The bond order denotes 1. the pattern in which Lewis dot structures oF atoms combine to Form bonds. 2. an estimate oF the strength oF a bond. correct 3. the order that orbitals are flled in electron confgurations. 4. an estimate oF the polarity or dipole mo- ment oF a bond. 5. the order oF flling oF bonding vs. anti- bonding orbitals. Explanation: Bond order is an estimate oF the stability oF the bond and hence the strength oF the bond. 005 3.0 points What hybridization would you expect For P in PO 3 ? 1. sp 2. sp 3 d 2 3. s 2 p 2 4. spd
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Version 217 – Exam 2 – mccord – (51600) 2 5. sp 3 d 6. sp 2 correct 7. sp 3 8. p Explanation: This is a resonance structure where P shares eight electrons with three oxygen atoms. There are no lone pairs of electrons. Therefore there are 3 regions of HED and the hybridization is sp 2 . 006 0.0 points If more points are awarded on this assign- ment, would you like them added to your score? 1. NO, leave my score alone, I prefer the lower score 2. YES, I would like the points and the higher score. correct Explanation: This should be a no-brainer. Most students want higher scores. If you picked yes, you got credit for the question and you got the extra points you asked for (if they were granted by your instructor). If you answered NO, you also got what you wanted. .. no points awarded. 007 3.0 points In the molecular orbital representation of ben- zene, the bonding between each C C pair is best thought of as 1. one sigma and half a delocalized pi bond. correct 2. one sigma and one pi bond. 3. one pi bond and half a delocalized pi bond. 4. one sigma and two pi bonds. 5. one sigma bond. Explanation: Six sigma bonding orbitals are formed from overlap of the 2 s atomic orbitals on the six carbons, and three pi bonding orbitals form a delocalized bonding system.
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This note was uploaded on 11/17/2011 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.

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Exam 2-solutions - Version 217 Exam 2 mccord(51600 This print-out should have 35 questions Multiple-choice questions may continue on the next

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