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Exam 2-solutions - Version 217 Exam 2 mccord(51600 This...

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Version 217 – Exam 2 – mccord – (51600) 1 This print-out should have 35 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 3.0points How many double bonds are in the compound CH 2 CHCH 2 CHCH 2 ? 1. 1 2. 3 3. 2 correct 4. 0 5. 4 Explanation: The Lewis dot structure is H C H C H C H H C H C H H 002 3.0points How many resonance forms are possible for the ethanoate ion? The formula for the ethanoate ion is CH 3 COO . 1. 2 correct 2. 4 3. 1 4. 3 5. 5 Explanation: The Lewis structures are C O H 3 C O C O H 3 C O 003 3.0points Which of the following is diamagnetic? 1. O 2 2. O 2 2 correct 3. O + 2 4. O 2 Explanation: All but O 2 2 are paramagentic (possess un- paired electrons). 004 3.0points The bond order denotes 1. the pattern in which Lewis dot structures of atoms combine to form bonds. 2. an estimate of the strength of a bond. correct 3. the order that orbitals are filled in electron configurations. 4. an estimate of the polarity or dipole mo- ment of a bond. 5. the order of filling of bonding vs. anti- bonding orbitals. Explanation: Bond order is an estimate of the stability of the bond and hence the strength of the bond. 005 3.0points What hybridization would you expect for P in PO 3 ? 1. sp 2. sp 3 d 2 3. s 2 p 2 4. spd
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Version 217 – Exam 2 – mccord – (51600) 2 5. sp 3 d 6. sp 2 correct 7. sp 3 8. p Explanation: This is a resonance structure where P shares eight electrons with three oxygen atoms. There are no lone pairs of electrons. Therefore there are 3 regions of HED and the hybridization is sp 2 . 006 0.0points If more points are awarded on this assign- ment, would you like them added to your score? 1. NO, leave my score alone, I prefer the lower score 2. YES, I would like the points and the higher score. correct Explanation: This should be a no-brainer. Most students want higher scores. If you picked yes, you got credit for the question and you got the extra points you asked for (if they were granted by your instructor). If you answered NO, you also got what you wanted... no points awarded. 007 3.0points In the molecular orbital representation of ben- zene, the bonding between each C C pair is best thought of as 1. one sigma and half a delocalized pi bond. correct 2. one sigma and one pi bond. 3. one pi bond and half a delocalized pi bond. 4. one sigma and two pi bonds. 5. one sigma bond. Explanation: Six sigma bonding orbitals are formed from overlap of the 2 s atomic orbitals on the six carbons, and three pi bonding orbitals form a delocalized bonding system. 008 3.0points What would be the electron geometry of the nitrogen atom in nitric oxide, N 2 O? 1. trigonal bipyramidal 2. octahedral 3. trigonal planar 4. linear correct 5. tetrahedral Explanation: The central nitrogen atom in N 2 O has only 2 regions of electron density.
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