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# WA7 - Robert E Goode MAT-231-GS004 Mentor Dr Paoletti...

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Robert E Goode MAT-231-GS004 Mentor: Dr. Paoletti 10/09/2011 Writing Assignment #7 Section 4.1 (24,28), Section 4.4 (12,14,16), Section 4.5 (22,30,64,68,74), Section 4.6 (16,26,32,34), Section 4.7 (2,8,14,20,30) Section 4.1 (24,28) 24. F(x) = x 2 +2x-4, [-1,1] F’(x) = 2x+2 =2(x+1) Left endpoint (-1,-5) Min Right endpoint: (1,-1) Max 28. g(x) = x 1/3 , [-1,1] g’(x) = 1/3x -2/3 left endpoint: (-1,-1) min Critical Number: (0,0) Right endpoint: (1,1) max Section 4.4 (12,14,16) 12. F(x) = 2x 3 -3x 2 -12x+5 F’(x) =6x 2 -6x-12 F’’(x) = 12x-6

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Point of inflection = (1/2,-13/2) When x <1/2 graph is concave down When x > ½ graph is concave up 14. F(x) – 2x 4 -8x+3 F’(x) = 8x 3 -8 F’’(x) = 24x 2 No point of inflection exists, graph is concave upward. 16. F(x) = x 3 (x-2) = x 4 -2x 3 F’(x) = 4x 3 -6x 2 F’’(x)= 12x 2 -12x = 12x(x-1) = 0 Point of inflection (0,0), (1,-1) When x<0 graph is concave up When 0<x<1 graph is concave downward When 1<x< infinity is concave upward Section 4.5 (22,30,64,68,74) 22. lim 3x 3 +2/(9x 3 -2x 2 +7) = 3/9 = 1/3 30. Lim -3x+1/(√(x 2 +x)/-√x) Lim (-3+(1/x)/(√(x 2 +x)/-√x 2 ) Lim (3-(1/x)/(√(1+(1/x)) = 3 64. Y = (x-3)/(x-2) Intercepts: (3.0), (0,3/2) There is no symmetry
Horizontal asymptote is at y=1 Lim (x-3)/(x-2) = 1

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