# WA1 - Robert E Goode Thomas Edison State College...

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Robert E Goode Thomas Edison State College MAT-129-OL009 Mentor: Nilajan Paul Writing Assignment #1 Section 4.2 8. Given: F(x) = 3 x and G(x) = (1/4) x , what is G(-3)? G(-3) = (1/4) -3 = 64 14. Graph F(x) = 4 x X F(x) 0 1 1 4 2 16 -1 .25 58. 32 t+1 =16 1-t (4 3 ) t+1 =(4 2 ) 1-t 4 (3t+3) =4 (2-2t) 3t+3 = 2-2t 5t = -1 T = -1/5 66. 1/81 = K -4 3 -4 =K -4 K=3 74. A= \$45,000(1 + .035/12) 12 \$46,600.51 Section 4.3

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4. 2 5 =32 therefore log 2 32=5 14. X=log 3 (1/81), therefore 3 x =1/81 X=-4 16. log x (27/64) = 3 X 3 = 27/64 X = (27/64) X=3/4 46. F(x) = log 10 X X Y = log 10 X 1 0 2 .301 3 .477 4 .602 5 .699 62. log 2 2 /5 Log 2 2 + log 2 -log 2 5 1+log 2 3 1/2 -log 2 5 1+1/2log 2 3-log 2 5 72. log b K + log b M - log b A Log b (K*M/A) 82. Given: log 10 2 = .3010; log 10 3 = .4771 Log 10 12 = log 10 2 + log 10 3 + log 10 2 Log 10 12 = .3010 +.4771 + .3010 =1.0791 Section 4.4 14 . log.078 = -1.108 (used calculator) 30. Limes, 1.6*10 -2 , ph=-log[1.6*10 -2 ]
Ph = -log 1.6 - log10 -2 Ph = -log1.6 +2 Ph = 1.80

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## This note was uploaded on 11/15/2011 for the course MAT 129 taught by Professor Unknown during the Fall '10 term at Thomas Edison State.

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WA1 - Robert E Goode Thomas Edison State College...

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