# WA2 - Robert E Goode Thomas Edison State College...

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Robert E Goode Thomas Edison State College MAT-129-OL009 Mentor: Nilajan Paul Writing Assignment #2 Section 5.1 (14,22,40,54,76,96,118,130) 14. (20x+10)° + (3X+9)° = 180° therefore 20 (7) +10 = 150° 23X +19 = 180 and 3(7) +9 = 30° 23X = 161 Hence the two angles are 150° and 30° X=7 22. (3x-5) + (6x-40) = 90° therefore 3(15) -5 = 40° 9x-45 = 90° and 6(15)-45= 50° 9x = 135° Hence the two angles are 40° and 50° X = 15 40. 180°-124° 51’ 179°60’ - 124°51’ = 55°9’ 54. 34°51’35” = 34° + 51°/60 +35°/3600 = 34°+.85°+.00972° = 34.8597° 76. Given = -203° 360° + (-203°) = 157°
96. Given: 225° Therefore 225° + n*360°= expression that represents all angles coterminal with 225°. 118. 130. 1000 rotations per min = 1000/60 = 16 2/3 rotations/sec 16 2/3*360° = 6000°/sec Section 5.2 (4,24,56,74,94) 4. X=-4 and y=-3
R = (x 2 +y 2 ) 1/2 =(16+9) 1/2 =5 Sinθ=y/r=-3/5; cosθ=x/r=-4/5 Tanθ=y/x=-3/-4=3/4 Cotθ=x/y=-4/-3=4/3 Secθ=r/x=5/-4=-5/4 Cscθ=r/y=5/-3=-5/3 24. Sinθ=y/r=-3/√(34) Cosθ=x/r=5/√(34) Tanθ=y/x=-3/5 Cotθ=x/y=5/-3=-3/5 Secθ=r/x=√(34)/5 Cscθ=r/y=√(34)/-3=-√(34)/3 56. Cscθ, given that sinθ=-8/43 1/sinθ=cscθ=1/(-8/43) = -43/8 74.