This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Derive this same result directly by calculating the rate at which the transverse force component F y does work on the next string element, which is moving with velocity v y . 6. A wave of frequency 500 Hz has a velocity of 350 m/s. (a) How far apart are two points 60° out of phase? (b) What is the difference in phase at a certain point at times 1.0 ms apart? 7. 13-40. Change: the string is fixed at both ends. Add: (e) what is the fundamental frequency? APPROXIMATE LECTURE SYLLABUS Chapter Lectures Topic 13 6/28-7/1 Waves in 1 dimension 14 7/2-7/8 Waves in 3 dimensions 29 7/9-7/13 EM waves 30-32 7/15-7/21 Geometric optics 33 7/22-7/27 Wave optics 35-36 7/29-8/6 Modern physics...
View Full Document
This note was uploaded on 11/16/2011 for the course PHYS 214 taught by Professor Thorne during the Summer '08 term at Cornell University (Engineering School).
- Summer '08