exam 2 solutions spring _09

exam 2 solutions spring _09 - EMA 3066 Exam 2 Name First...

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Unformatted text preview: EMA 3066, Exam 2 February 26, 2009 Name: First Last I have neither given nor received help on this exam. Signature 1. Production of a nylon fiber requires spinning the fiber at a speed of 200 Wminute. If fiber is extruded through a hole 1 mm in diameter and the length of the hole is 5 cm, what is the pressure drop required (in units of atmospheres) across that hole? The viscosity for _ nylon under the processing conditions is 1400 poise. . -3 Q = 31o: *3 7‘ {T'(a-5‘¥/a m) (0‘1 ‘3 9~_ _ - J-GEL‘HU .Q/s _._ c... -3 R h C3--"7(/0 :‘v1 4 P ‘37 (IL/c RAMs/0'23(Dram/o‘hi/sh i? ( an 3—)(/0_3 a} L/ 3 i. {1’ ' 7 Li 7’ 300 .lIDc_- b X ?-B7%/ohtln—1‘r\ ‘ Pm ': 7'7DKEO (Ff/h EMA 3066, Exam 2 February 26, 2009 2. Describe the synthesis of a styrene-butadiene diblock copolyrner that contains a styrene block length of 500 repeat units and a butadiene block length of 100 repeat units. Include the steps of the synthesis and the concentrations of initiator and the monomers. )r) ta rd er ‘l‘t. QL: L‘wf’ {11433 L336. 0- I [xvi/i <3 "--. fclyme-Igp-Hmi wkdx mews c—m‘m. L_ alt!) l i LUe {16663 a“ ((4 5‘00 glyrevt? ,—-(/0c=;..f VICTS‘ FL)"; EA PEI/H L X,., : fig ,‘4 (D 6 awe I C‘ ("7.- (' on “13/ “J FUN . 6"" I‘VE I’lt’é’é “‘9 W 5‘0 1.! ‘- l fi‘l‘Zr‘fl-«t’t :.m7‘ll"l"r 'fli‘h—C' . :5 50-7 H L")? \ hk‘cnk,f (sni+*._1‘r:,‘l“t\‘-"\ 5" 71+er 18', m We (at/ft“ [’11. \rv fl ’5 )J'f‘c’f'q‘l. ‘ 1')\ TU Ale-‘43. u—"l CL If +12 0 L" J I“ fr Fr 'v ' ‘3 I “(h l‘ a F.fiTl“Ié~—')'t"r 50- fiat; ’570fi/G l,)‘_.\‘.|lr/Z_ ‘( liq-T { u ‘e- (+er ‘4. ch 47m”, (“b-it’d. EMA 3066, Exam 2 February 26, 2009 3. On the desks are envelopes containing a polymer sample (all the envelopes have the same polymer). Examine this sample and determine the following: I Is the polymer crystalline or amorphous? If crystalline, provide an estimate for the %crystallinity. Is the Tg above or below room temperature? Is the Tm above or below room temperature? What polymer do you think it could be? You must explain how your observations led to the answers that you give. " (J I" 0 (use I 60 594’»? L;‘ y's‘l‘ u/‘(g‘né '_ e Eb If? Hr ILKUHY r a ‘ . 1 ‘I r. I (5/515 Ztyt’ ‘fi({ ét’L-[FIY {atth ,‘J .3, jgrcbké/‘y lwt‘lfvyyj C f7 Cri- “INl-fir j .m i7’0 v ((7. CJ' 767 - T— ? fulfil" 6.1/1 /3_t;_fie+f h {(4 /(I 5‘. 7w T”) TC” be [04:- f (2 om Fr" --"l W1"— SIK-M 9 iii lb (fluid. ’y‘j‘JhA‘P ' ot" Tl I‘D (1.1 t A!“ ll :5 ‘n- 10" J"? (Own lie-«7" V—u fur-t” . 1») it,“ L‘7.g"’gr/,|‘:fl,{7/ ‘lc’cv {7-9 :1; (of? c"/“I c1 "low-.5 9 pres} _ m. I It. 3 6: v Tb( ( N2: ‘l‘7 T"‘* 5 “3" {97' (’0 {/7 X I Aft—1w “Fat/re “,1 film“ C}! "W \l“ “Div? 0 n €63»! lr’fi l' (l E t t’ 1"? fa v Tb C P ’r 1k/ ’ Alfit’l. we .m‘fl' (“w-FL? flaw-P Ifik’ertrrn) A4th (1-)?) (,1 m-ch’o/t r—‘w Vx‘thjlly— all'“‘~t— "I", bud/34 "‘ Cltk. r“ 'w x-‘x VTSr & I: l)’ flr’w AH.» Mh‘r‘l 13‘: j‘M'fi “Zn-IL R A 3.“! _ — ,0. 0—; r a“ CJ‘d-Atjin.) EMA 3066, Exam 2 February 26, 2009 4. A particular polymer with a weight average molecular weight of 500,000 g/mol is being processed at 250‘I C, but there are problems because the polymer is degrading at that temperature. Therefore you decide to reduce the processing temperature to 200° C. However, you need to make sure that the viscosity under the new processing conditions is the same as what it was under the old conditions. What molecular weight should the polymer be under the new processing conditions so that the viscosity at 250° C and 500,000 g/mol molecular weight is the same as the viscosity at 200° C and the new molecular weight? For this polymer, the activation energy for flow is 95 kamol, the entanglement molecular weight is 15,000 g/mol, and the glass transition temperature is 80° C. Pits} so ,d m a“. t, H) Visceral), (LlflMBQ “vac _____ 311 3.4 mad :- MW“, /0 L77 31' {/37 H / fl/VVJT f— (yt'lfl'r‘vl: : 2 C) 3, 5 U0 ’/) .«h/ /fr’.-C7 EMA 3066, Exam 2 February 26, 2009 5. Neglecting endgroups, calculate the conversion needed to obtain a number average molecular weight of 24,000 g/mol for the following monomer. What is the weight average molecular weight and PD] of the polymer that results? 0 || HO--f-CH2-)l-4—C—0H ff c, d I .5 JD (17.4.4! Win = 3 ‘1} cl/ww 4 : :2 "L cmcv 3/”) 'J .‘v {I ' --————" —'_" A1,?/,(_f_ Ma -_ -- .. . - J ['t’wr JSVC/D-II’ r- fif..vc-”E + ly/Tftfr/(y 1 lib/o, 9;? 42/4 0—4—1 ‘ t ;K/,~— Xh ': l l-)‘) P Ken/'3 ._-:. kfi": _ Qn—I F - 0.4%?" 29-. EMA 3066, Exam 2 February 26, 2009 6. For each of the following products, provide the processing technique that would be most appropriate. Provide a brief (1 sentence) explanation for your choice. a. A prototype of a new style of plastic cup to Show your boss. C o ‘3: . T3 L A C’ of (marl 8/57 0 fie“ flat 7“, lyric?" b. A new style of plastic cup for large scale production. Injecl‘r\/‘ fl'V'I'fCi-xnrbv Ctr/‘- flfidv'it". (Mr/x)! (“v/.5") rZ-Jkgffn 0. Plastic wrap for food (like Saran wrap). Erratic/u (5ft? 1: QUE/y L/a-‘Ld (fl/h f’gf-v-Jf-n—x) (- a k div \3‘. (F/‘lfr‘jfin—fi—v ) )krn c' (i C (/‘LJmF‘THHJ' .r'c’ris _ (){PE 'AI . £'/"| (:1. Drinking straws. L: fl'l/ v£3l~tfl .. C wra 4 X“ c d .. \L f’. .71 (I 47 4.3515”; W ‘2 a / (afigl‘w‘hl CI": ‘35- Sec 'l‘zkn ?LI‘TLK[7. e. Afoam ball. 199...: Hm [-58 ,. +:.,,. mam, :ij ,. H c.-.,. (.2. mm, Frrd-W'Lt’ {ntmu/ 1Com” chl-lv-L’LAtJ r’Y‘c.-n.--{") 'lC: ((vtklé "'€‘_‘-+ ’Wfé_ EMA 3066, Exam 2 February 26, 2009 EMA 3066 Exam 2 Equation Sheet no —17.44(T—Tg) neg = 51.6+iT—Tgi & "a = AeRT no =Bfi§.,a: 1.0 or 3.4 1 Pa—s = 10 P R = 8.314 Jimol—K 1 Pa = 9.87x10‘fi arm EMA 3066, Exam 2 February 26, 2009 Periodil- Table of the Elements IA Key Elam: number . Cu T—Symbal '4‘ Intermeduate I 535.1 Atomic weight IIIA M I_ _ _ ; Nb-Mo 2 9] 95.9: ?3 4 Ta W . 5 so I 51 . . ' Rareeatth series La | (Le Pr _ Nd 3m TD Dy mama-1.2a n45: - 153.92 162.50 16ml fictunlde set-es 'I . ' ‘ {24h ...
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exam 2 solutions spring _09 - EMA 3066 Exam 2 Name First...

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