HW4solf10

# HW4solf10 - Homework#4 Solutions 1 Since the conversion is...

This preview shows pages 1–2. Sign up to view the full content.

Homework #4 Solutions 1. Since the conversion is 100%, p=1, and since all but part a have unequal numbers of reactants, the correct equation to use is: x n = 1 + r 1 r Note that the following equation: x n = 1 1 p is not the correct equation to use, because it is only for stochiometric equivalence (equal numbers of reactive groups), and gives the chain length as a function of conversion. a. r = 2 moles diol 2 moles diester = 1.0 x n = 1 + 1.0 1 1.0 = ∞ b. r = 2 moles diol 4 moles diester = 0.5 x n = 1 + 0.5 1 0.5 = 3 c. Since r must be less than 1.0, we need to calculate it as follows: r = 2 moles diester 4 moles diol = 0.5 x n = 1 + 0.5 1 0.5 = 3 d. r = 45 moles diester 50 moles diol = 0.9 x n = 1 + 0.9 1 0.9 = 19 2. For a homogeneous free radical polymerization, the rate and chain length are given by: [ ][ ] [ ] [ ] 2 / 1 n 2 / 1 p I M X I M R α α These equations are equivalent to saying:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
[ ][ ] [ ] [ ] 2 / 1 n 2 / 1 p I M b X I M a R = = where a and b are unknown constants. For the first case, we want to increase the rate 50% by
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

HW4solf10 - Homework#4 Solutions 1 Since the conversion is...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online