EMA_4314_HW6_solutions

EMA_4314_HW6_solutions - EMA 4314 HW 6 Solutions ...

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Unformatted text preview: EMA 4314 HW 6 Solutions Discussion questions 6.1 6.3 Exercises Problems 20.26 The diffusion equation is: 2 ∂C ∂ C =D 2 ∂t ∂x From eq. 20.57: € ∂C − nO −3 / 2 −x2 nO x 2 −5 / 2 −x 2 = t • exp( )+ t • exp( ) ∂t 2 A πD 4 Dt 4 A πD 4 Dt € ∂ 2C −nO −x 2 nO x 2 −x2 = t −3 / 2 • exp( )+ t −5 / 2 • exp( ) ∂x 2 2 A π D 3 / 2 4 Dt 4 A π D3 / 2 4 Dt By inspection, the diffusion equation is satisfied. € ...
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This note was uploaded on 11/16/2011 for the course EMA 4314 taught by Professor Phillpot during the Fall '10 term at University of Florida.

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