Exam 2 - 2nd Version-Solution

Exam 2 - 2nd Version-Solution - Name_Solution Yellow EMA...

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Name____Solution - Yellow____ EMA 4314 Fall 2010 Exam #2 (100 points) There are four questions, each worth 33 points (you get 1 point for writing your name above). You will receive credit for 3 questions only; if you attempt all 4, you will get credit for the best 3. Question 1 [Phase transitions] a. On the axes below sketch the temperature dependence of the chemical potential for the solid, liquid and vapor phases. Show the transition temperatures and identify the slopes in terms of a thermodynamic state function. (7 points) b. Explain the meanings and applications of the Clapeyron Equation and the Clausius-Clapeyron Equation. (8 points) The Clapeyron equation is dP/dT = S/ V. It gives the slope on a P-T plot of a phase line. The Clausius-Clapeyron Equation is the application of the Clapeyron equation to the liquid- vapor transition. The specific form is determined assuming that the vapor is an ideal gas. c. On the set of axes below, sketch the phase diagrams of H 2 O and a CO 2 (a solid that melts in a conventional manner): don’t worry about the specific values: it’s the general shape that is important. (10 points) d. How is the slope of the solid-liquid phase boundary determined from the Clapeyron Equation? Make particular reference to any differences between CO 2 and H 2 O (8 points)
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The Clapeyron equation is dP/dT = S/ V. For a solid liquid, solid vapor, or liquid
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This note was uploaded on 11/16/2011 for the course EMA 4314 taught by Professor Phillpot during the Fall '10 term at University of Florida.

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Exam 2 - 2nd Version-Solution - Name_Solution Yellow EMA...

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