EMA4223 HW7 Solutions

EMA4223 HW7 Solutions - Â we obtain m=5.9~6 and σ o =476...

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7.24 Using the Weibull Equation, establish the tensile strength, with a 50% survival probability, of specimens with a length of 60mm and a diameter of 5mm. Uniaxial tensile tests carried out on specimens with a length of 20mm and the same diameter yielded the following results in MPa (10 tests were carried out): 321, 389, 411, 423, 438, 454, 475, 489, 497, 501. If N samples are tested we rank their strengths in ascending order; obtain their failure probability (±) ² ³ ´ µ ³ Thus, Test F(V) Strength (σ) 1 0.05 321 2 0.1 389 3 0.14 411 4 0.19 423 5 0.24 438 6 0.29 454 7 0.33 475 8 0.38 489 9 0.43 497 10 0.48 501 Now plotting ¶·¶· [ ¸ ¸¹º(») ] ² ¼½(¶¾¿À Á ¶¾¿À
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Unformatted text preview: Â ) we obtain m=5.9~6 and σ o =476 m o o V V V P exp ) ( MPa 373 ) 476 ln( 6 ln 6 ] 5 . ln 60 20 ln[ 476 20 60 exp 5 . 6 7.47 Engineers are design a ceramic component for a jet engine. The ceramic has a fracture toughness of 8 Mpa m1/2. The ceramic is subjected to a maximum tensile stress of 500 Mpa. Calculate the maximum size of surface flaws that the part can have. 1 500 8 2 a m a m a 5 . 81 10 15 . 8 5...
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This note was uploaded on 11/16/2011 for the course EMA 4223 taught by Professor Mecholsky during the Spring '08 term at University of Florida.

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EMA4223 HW7 Solutions - Â we obtain m=5.9~6 and σ o =476...

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