pasha (sep635) – HW #31 – Antoniewicz – (56445)
1
This printout should have 23 questions.
Multiplechoice questions may continue on
the next column or page – fnd all choices
beFore answering.
001 (part 1 of 4) 3.0 points
Each part oF this problem will state an ex
ample oF objects interacting via some Force.
Choose the Fundamental interaction that is
responsible in each case.
Aneu
tronou
ts
ideanuc
leusdecaysin
toa
proton, electron, and antineutrino.
1.
Strong
2.
Electromagnetic
3.
Gravitational
4.
Weak
correct
Explanation:
Notice the presence oF an antineutrino in
this decay. Neutrinos (and their antiparticle
partners) only interact via the weak Force, so
this must be a weak interaction.
002 (part 2 of 4) 2.0 points
Protons and neutrons attract each other in
anuc
leus.
1.
Gravitational
2.
Strong
correct
3.
Electromagnetic
4.
Weak
Explanation:
The Force that holds the nucleus together
must be
strong
enough to overcome the repul
sion between protons due to the electromag
netic Force. This is a strong interaction.
003 (part 3 of 4) 2.0 points
The Earth pulls on the Moon.
1.
Gravitational
correct
2.
Strong
3.
Weak
4.
Electromagnetic
Explanation:
This is a gravitational interaction, in which
massive bodies attract each other.
004 (part 4 of 4) 2.0 points
Protons in a nucleus repel each other.
1.
Weak
2.
Strong
3.
Gravitational
4.
Electromagnetic
correct
Explanation:
This is an example oF an electromagnetic in
teraction, in which particles with like charges
repel.
005 (part 1 of 2) 5.0 points
The mass oF the Sun is 2
×
10
30
kg, and
the mass oF Mercury is 3
.
3
×
10
23
kg.
The distance From the Sun to Mercury is
4
.
8
×
10
10
m.
±irst, calculate the magnitude oF the gravi
tational Force exerted by the Sun on Mercury.
Use
G
=6
.
67
×
10

11
m
3
kg
·
s
2
.
Correct answer: 1
.
91068
×
10
22
N.
Explanation:
The magnitude oF the gravitational Force
between two objects is given by
±
±
±
~
F
gr
±
±
±
=
±
±
±
±

Gm
1
m
2
r
2
±
±
±
±
=
Gm
1
m
2
r
2
.
We just need to plug in the given constants to
fnd the answer:
±
±
±
~
F
gr
±
±
±
=
Gm
1
m
2
r
2
=
(
G
)(2
×
10
30
kg)(3
.
3
×
10
23
kg)
(4
.
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View Full Documentpasha (sep635) – HW #31 – Antoniewicz – (56445)
2
=
1
.
91068
×
10
22
N
.
where
G
=6
.
67
×
10

11
m
3
kg
·
s
2
.
006 (part 2 of 2) 4.0 points
Calculate the magnitude of the gravitational
force exerted by Mercury on the Sun.
Correct answer: 1
.
91068
×
10
22
N.
Explanation:
By Newton’s third law, and by simply look
ing at the formula for the gravitational force,
it is clear that the force exerted by Mercury
on the Sun will be the same as that exerted
by the Sun on Mercury.
007
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 Fall '08
 Turner
 Correct Answer, Fundamental interaction, pasha

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