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Unformatted text preview: pasha (sep635) – HW 4-4 – Antoniewicz – (56445) 1 This print-out should have 26 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 5.0 points If an object is moving with constant momen- tum ~ p = h 10 ,- 10 ,- 10 i kg · m / s , what is the magnitude of the rate of change of momentum d ~ p dt ? Correct answer: 0 kg · m / s. Explanation: A constant momentum implies that the rate of change of momentum is zero. 002 (part 2 of 2) 5.0 points What is the magnitude of the net force acting on the object? Correct answer: 0 N. Explanation: By the Momentum Principle, Δ ~ p = ~ F net Δ t, if the rate of change of momentum is zero, then the net force is also zero. 003 (part 1 of 4) 3.0 points A ball whose mass is 1 . 2 kg is suspended from a spring whose sti ff ness is 5 N / m. The ball oscillates up and down with an amplitude of 13 cm. Take g = 9 . 8 m / s 2 . What is the angular frequency ω ? Correct answer: 2 . 04124 rad / s. Explanation: The angular frequency is given by ω = r k m = s 5 N / m 1 . 2 kg = 2 . 04124 rad / s . 004 (part 2 of 4) 3.0 points What is the frequency? Correct answer: 0 . 324874 s- 1 . Explanation: The frequency is given by f = ω 2 π = . 324874 s- 1 . 005 (part 3 of 4) 2.0 points What is the period? Correct answer: 3 . 07812 s. Explanation: The period is given by T = 1 f = 1 . 324874 s- 1 = 3 . 07812 s . 006 (part 4 of 4) 2.0 points Suppose this apparatus was taken to the Moon, where the strength of the gravitational field is only 1/6 of that on Earth. What would the period be on the Moon? (Consider care- fully how the period depends on properties of the system; look at the equation.) Correct answer: 3 . 07812 s. Explanation: This period is the same as the period you found in part 3, since g does not enter the formula for T . 007 10.0 points A mass of 5 kg is connected to a horizon- tal spring whose sti ff ness is 19 N / m. When the spring is relaxed, x = 0. The spring is stretched so that the initial value of x = 0 . 2 m. The mass is released from rest at time t = 0. Remember that when the argument of a pasha (sep635) – HW 4-4 – Antoniewicz – (56445) 2 trigonometric function is in radians, on a cal- culator you have to switch the calculator to radians or convert the radians to degrees....
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This note was uploaded on 11/17/2011 for the course PHY 303K taught by Professor Turner during the Fall '08 term at University of Texas.
- Fall '08