QTest #3-solutions - Version 127/ABDDD QTest #3 Antoniewicz...

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Version 127/ABDDD – QTest #3 – Antoniewicz – (56445) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points Ac h a r g e dp a r t i c l ei sa c t e du p o nb ya Force oF magnitude 120N over a time t. Given that the initial momentum is (15 , 10 , 0) kg.m/s and that the fnal momen- tum is (20 , 20 , - 10) kg.m/s ,fnd t and the Force F (in Newtons). 1. 0.125s, (40 , 80 , 80) N 2. 0.25s, (20 , 40 , - 40) N 3. 0.125s, (80 , 40 , 40) N 4. 0.25s, (20 , - 40 , 40) N 5. 0.125s, ( - 80 , 40 , 80) N 6. 0.125s, ( - 40 , - 80 , 80) N 7. 0.125s, (40 , 80 , - 80) N correct Explanation: Given that ~ p i =(15 , 10 , 0) kg.m/s ~ p f =(20 , 20 , - 10) kg.m/s ~ | F | =120 N We use the Formula For the magnitude oF the impulse = | ~ p f - ~ p i | = | ~ F | t t = ( | ~ p f - ~ p i | ) | ~ F | =0 . 125 s ~ F = ( ~ p f - ~ p i ) t =(40 , 80 , - 80)
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QTest #3-solutions - Version 127/ABDDD QTest #3 Antoniewicz...

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