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QTest #5-solutions

# QTest #5-solutions - Version 008/AAACA QTest#5...

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Version 008/AAACA – QTest #5 – Antoniewicz – (56445) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A 4 kg metal block slides along the floor. The coe ffi cient of sliding (or kinetic) friction between the block and the floor is 0 . 64. The initial speed of the block is 6 m / s. How far does the block slide before coming to a stop? 1. 2.8699 2. 3.90795 3. 2.7414 4. 5.10204 5. 15.3061 6. 5.92495 7. 4.47984 8. 7.65306 9. 9.66702 10. 4.96415 Correct answer: 2 . 8699. Explanation: Let : m = 4 kg , g = 9 . 8 m / s 2 , v i = 6 m / s , and μ k = 0 . 64 . We know that the frictional force f k is given by - μ k F N where F N is the normal force and equal to mg . Thus, we make use of the rela- tion v f = v i + f k m Δ t = v i - μ k ( mg ) m Δ t But, the final velocity is zero since the block comes to a stop. 0 = 6 m / s - (0 . 64)(9 . 8 m / s 2 ) Δ t Δ t = 0 . 956633 s The distance covered is given by x f = x i + v i Δ t + f k 2 m Δ t 2 = x i + v i Δ t - μ k ( mg ) 2 m Δ t 2 = 0 + (6 m / s)(0 . 956633 s) - (0 . 64)(9 . 8 m / s 2 ) 2 (0 . 956633 s = 2 . 8699 002 10.0 points L b Mg

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QTest #5-solutions - Version 008/AAACA QTest#5...

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