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Homework 3 Solutions Part 1

Homework 3 Solutions Part 1 - Homework 3 solution 2 Since...

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Homework 3 – solution 2. Since the random variable ˆ Θ θ has a distribution with known critical values we can write Pr ˆ f 1 - α/ 2 ˆ Θ θ f α/ 2 ! = 1 - α A little algebra allows us to rewrite this to give a 100(1 - α )% confidence interval on θ : Pr ˆ ˆ Θ f α/ 2 θ ˆ Θ f 1 - α/ 2 ! = 1 - α. So the desired interval is " ˆ
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