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Unformatted text preview: November 3 Physics In: If 400 Joules of work is done lifting this 10 kg box, how high did it go? Objective : To continue our study of energy Success criteria: Be able to solve problems of: work, kinetic energy work/kinetic energy theorem gravitational potential Homework check Work: Work=force x distance Force and distance must be in the same direction Work/Kinetic energy Theorem The work done on an object equals the change in kinetic energy of the object: Work=KE 2KE 1 Problem: A man lifts a 10 kg cat a distance of 2 m, how much work did he do on the cat? Problem: A 10 kg cat is dropped from a height of 2 m. Just before it lands, it has a speed of 6.3 m/s, what is it’s kinetic energy? A 2000 kg car goes from 0 to 60 m/s. How much work was done? It took 100 meters to accelerate. How much force was used? A 2000 kg truck going 20 m/s hit a tree and crumpled .5 meters. What was the force on the tree? Work=KE2KE1 Fxd=01/2mv 2 F(.5)= 1/2(2000)20 2 F= 400,000/.5 F= 800,000 N...
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This note was uploaded on 11/18/2011 for the course PHYS 121 taught by Professor Burgeson during the Fall '11 term at BYU.
 Fall '11
 Burgeson
 Energy, Kinetic Energy, Work

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