IRWIN 9e 12_40

IRWIN 9e 12_40 - Irwin. Basic Engineering Circuit Analysis....

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis. 9/E 1 124::- .5. pzu'ullcl Rb? circuit. which i5 driven by a vzu'iuhlc t'rcqucncy‘ 2—H current ranuruc. hiifi 1hr: {alum-mg vuluca: R = 1 MC]:~ L = IUD mH. uml C = 1C! pJF. Fiml the bandwidth Inf the network. the half-power ['rcqucncjca. 21ml the run-ago mums the network at tho half—pnwer 1'1'eLl1Ie11uicH. SOLUTION: 8w :- ._L_. —-» ‘ QC (Ix/Q3)CIOXID’6) 8w — loo aid/A (DD: ‘ :: ‘ (D: {O x WHJ 2: W0 [ ‘TL 2Q \) 2&3 z + 5 an] 2-00) 200)» Ml : 3051.25 9104/8 NHI : [ODD Chapter 12: Variable — Frequency Network Performance Problem 12. 4O 2 Irwin, Basic Engineering Circuit Analysis, 9/E WLO: [N01 : Q9951): WM: [051-25 '- -— Y: _L+ J... + Zc. K Z i: 240°A V: L 7’ \7(JWHI) : ——L——+ ‘ TJ(!O5J'25)(lOp) ‘ ’000 J(i05i-25)(ioomo'g) y(J'Win) :' HJ” 'mS ijm)‘ = I + l +J’{45I.25)[(0A) loco J'QS’inS(iooxiD'3) 57“ mm) 3 "J" m3 V: 22.49:.— (HJ‘I) m \7: J: [45° KV Oi WHI \7: 2LO° {MD M E Problem 12.40 Chapter 12: Variable -— Frequency Network Performance Irwin. Basic Engineering Circuit Analysis, 9/E 3 V: films") i<v out wow _________—_.____—..___—————.——————————I-— Chapter 12: Variable — Frequency Network Performance Problem 12. 40 ...
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This note was uploaded on 11/21/2011 for the course EE 2120 taught by Professor Aravena during the Fall '08 term at LSU.

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IRWIN 9e 12_40 - Irwin. Basic Engineering Circuit Analysis....

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