IRWIN 9e 12_41

IRWIN 9e 12_41 - lnrvin, Basic Engineering Circuit...

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Unformatted text preview: lnrvin, Basic Engineering Circuit Analysis, 9/E 1 __________________________—_.__ 1241 A pzouh‘l RLC circuit. which is LII'jL'L‘fl h}; a variable frequency 2—9.. current Hmrruc. hair; the I'nllrm-irrg L'ulucg: R = 1 RH. L = 400 mH. and C = 10 hF.FimI1he bandwidth 01' the rmwnr'k. the half—jumrr' t'r‘cqucncr'ca. uml the whugc hummer 1hr: hem-wk at tho half—jum'cr' t'r‘cqucncica. SOLUTION: (rooox roxr0”6) 8 (Id :» ’00 acid VS - i : I , M _____________,__,______. \ILC Wt): 500 mam U30 Chapter 12: Variable — Frequency Network Performance Problem 12. 41 2 lwvin, Basic Engineering Circuit Analysis, 9/E LUHI : 552.5 mad/8 DULO : WHI” BUG : - [OD WLQ: q5’l‘ 5 +j 552.1% mm“) “I000 J (552.5)(qooxro‘3) YUle) : I+Jl rm: WJ-wm): ; + I finszsooxzo“) IOOO J'LISz-5(woo><10‘3) Y()U)Lo)'~'— I-jl W5 1 37 Problem 12.41 Chapter 12: Variable — Frequency Network Performance Irwin, Basic Engineering Circuit Analysis, 9/E V(]LA)HI) : 210° 1 <i+"J'i>wo~3 f —-—-———————————.—_____—_—__—__ Chapter 12: Variable — Frequency Network Performance Problem 12. 41 ...
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