{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

IRWIN 9e 12_43

# IRWIN 9e 12_43 - Irwin Basic Engineering Circuit Analysis...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 1 1.24.3 The ssuuree in the nelwiur}; in Fig. P114?- is is“) = unslﬂﬂﬂr + uualﬁﬂﬂr .-—'i.. R = EEK} ﬂ and C = SCH] iiF. lt' mg = 1000 i'uilfeg. 1'iml L. Q. and the B151". Cumpule the mllput Full-L130 1'9“) and diHL‘LIh‘H the magnitude iii' the output voltage 211 the two input frequencies. Figure P1243 SOLUTION: :7 I “U019 Q 0 005% 500 mo") L: ZMH 8w :: i :2 I RC 200[ 500Xi0'6) (Q: W0 :: [ODD 13w (0 (Q : {00 7:. Jr [ 'I' i L {/- igoo) 2: I i— +J' (loco) ( Scowd‘j i Chapter 12: Variable ~ Frequency Network Performance Problem 12. 43 2 Irwin, Basic Engineering Circuit Analysis, 9/E —— YCJ'iooo) = 5mg 37(j 1500):: __L. + __'.____._jj(asoo)(500><(0") 200 j!500()_)( [0"3) V0500) : 5+J'L4i'iwms We &u.;aexpozihbnr {)0 . iéo" ‘ 5M63 {70' Z 200 AO° V —_—_—_—__—__—_———————————4— Problem 12.43 Chapter 12: Variable — Frequency Network Performance lnNin, Basic Engineering Circuit Analysis, 9/E 5x53 +J' Hm Xio’3 V01: 2"“! L-S’QGIO V \$0105): 200608 [0001 V Tl01(46): 2M waOB'OQt vim-3,0) V Vow: {70,(t) + 031%) ~ 000:) : 2‘00 (195’ loco: + Z'Hcos ( leokvizq‘3I°)V Chapter 12: Variable — Frequency Network Performance Problem 12. 43 ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online