IRWIN 9e 12_75

IRWIN 9e 12_75 - IMin, Basic Engineering Circuit Analysis,...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: IMin, Basic Engineering Circuit Analysis, 9/E 1 12.]!5 Given the circuit in Fig. 125?. Liflfiigil Ei ECCUflLi-tfiflii‘f hand—11mm film with a mentor t'i'i‘qui‘ncy' gain 01' —5. mu = 50 kaiLift'lH.i11]LiEtB1'i"-'I = 10 ki'udg’e. Li‘t C1 = C2 = C and R1 = 1 RH. What i.~t the 4;} iit'thie; t'iiti‘i”:1 Sketch the BULIC pint t'tii' the fiitL‘T. Um: the idea] tiji—ttiitji intrude]. SOLUTION: Fhonv tho £€Ltt rz '/ (/00: i+ ‘élz— Z W 1' 50!: %ad/5 I 7. \Ao : Bk): 2c «2 95‘ i 8w: Log " M?— 1” 'OK Mat/2 Q Center WWUCW, 9am: :E—ET—~ 1‘5: Ho 21: JQRI RL: “3(1000) £2: [OKJL Chapter 12: Variable -— Frequency Network Performance Problem 12. 75 2 Irwin, Basic Engineering Circuit Analysis, 9/E 9.2””! : ___2____.____.__._._. 9228‘” ('OOOO)C(OOQQ) C: 20m: Q3: 12 w01R|R1C24 R5: w (5OOOO)I( i000)(i0000)(20){16q) -| “3 2 ii i_r2_ Q 2 .231, 8w Q: 50000 [0000 CG: 5 Hm: Howard) (32 $2 7‘ 281415 '1' L059“ 32+ 2x104 cf 29%? Vow ewiaa: g: 404 i [ii-CW3“ Chad/L ' s Problem 12.75 V Chapter 12: Variable — Frequency Network Performance InNin, Basic Engineering Circuit Analysis, 9/E V ‘ 3 Wm)! [519314392 0 “20 [.HCjw) (cleaves) a. 210 I38 Problem 12. 75 Chapter 12: Variable —— Frequency Network Performance ...
View Full Document

Ask a homework question - tutors are online