IRWIN 9e 12_75

# IRWIN 9e 12_75 - IMin Basic Engineering Circuit Analysis...

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Unformatted text preview: IMin, Basic Engineering Circuit Analysis, 9/E 1 12.]!5 Given the circuit in Fig. 125?. Liﬂﬁigil Ei ECCUﬂLi-tﬁﬂii‘f hand—11mm film with a mentor t'i'i‘qui‘ncy' gain 01' —5. mu = 50 kaiLift'lH.i11]LiEtB1'i"-'I = 10 ki'udg’e. Li‘t C1 = C2 = C and R1 = 1 RH. What i.~t the 4;} iit'thie; t'iiti‘i”:1 Sketch the BULIC pint t'tii' the ﬁitL‘T. Um: the idea] tiji—ttiitji intrude]. SOLUTION: Fhonv tho £€Ltt rz '/ (/00: i+ ‘élz— Z W 1' 50!: %ad/5 I 7. \Ao : Bk): 2c «2 95‘ i 8w: Log " M?— 1” 'OK Mat/2 Q Center WWUCW, 9am: :E—ET—~ 1‘5: Ho 21: JQRI RL: “3(1000) £2: [OKJL Chapter 12: Variable -— Frequency Network Performance Problem 12. 75 2 Irwin, Basic Engineering Circuit Analysis, 9/E 9.2””! : ___2____.____.__._._. 9228‘” ('OOOO)C(OOQQ) C: 20m: Q3: 12 w01R|R1C24 R5: w (5OOOO)I( i000)(i0000)(20){16q) -| “3 2 ii i_r2_ Q 2 .231, 8w Q: 50000 [0000 CG: 5 Hm: Howard) (32 \$2 7‘ 281415 '1' L059“ 32+ 2x104 cf 29%? Vow ewiaa: g: 404 i [ii-CW3“ Chad/L ' s Problem 12.75 V Chapter 12: Variable — Frequency Network Performance InNin, Basic Engineering Circuit Analysis, 9/E V ‘ 3 Wm)! [519314392 0 “20 [.HCjw) (cleaves) a. 210 I38 Problem 12. 75 Chapter 12: Variable —— Frequency Network Performance ...
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