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8.3modified_RangeOfValues

# 8.3modified_RangeOfValues - PROBLEM 8.3 Determine whether...

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Unformatted text preview: PROBLEM 8.3 . Determine whether the block shown 1s in equilibrium and ﬁnd the magnitude and direction of the friction force when 0: 40° and P: 400 N SOLUTION Assume equilibrium: = : N— (800 N)cos 25° + (400 N)sin 15° = O a N=+621.5N N=621.5NI LT- : -—F + (800 N)sin 25° — (400 N)cos 15° = O 1 55 F = +4828 N F = 48.28 N \ 2 Maximum friction force: M \$5 = 0.20(621.5 N) i 3 = 124.3 N Block is in equilibrium 4 " SinceF<Fm, ' F=48.3 N \ 4 F, A A, ”ii/ML m/A%zy a? “4,5qu €71 P +0 Vicki "the, Hook; 3% abort: E: 300M I 7 Verge oi: 5‘ 01% W “A? 3F)! :0 40°— 75” 245° 300M ywsﬁ" +NA + Psmi 5° {:0 wk Z ZFX’= O a A!» \$05M “25°—,2 NA — Pcoslg 1 0 x>=2\\.27—N NA‘970'7’8N ,. ZF =0: same. as above, y! ’ZNA 2F)" :0 NA I SOON sinZSa +,7.NA - P055 '50 3 O P=474.72N 514,; new?” ?M‘N: ZH.ZZ N (REM? b-siiée (lower) V PMAX: 474.7'N (ﬁbeu‘i' +0 SKA—ﬂ UP) ...
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