211_5TrussProbs_solns

211_5TrussProbs_solns - WW“... ‘1.“ . 4/11 A snOW...

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Unformatted text preview: WW“... ‘1.“ . 4/11 A snOW load transfers the forces shown to the upper joints of 21 Pratt roof truss. Neglect any horizontal reactions at the supports and compute the forces in members BH, BC, and CH. {Rp‘O "‘1’ iFy’=() BC= 33. své/U (<7)... =20 kN ,AB fl; ~5+Qo :o A B = RR) = 395% U 33% 9/5 #14: 30 AN zfj’ro 3H “Xi/0M v 3 \ J ., ’\, :/ /0kNl“’ f Ans. BC = 3.00 kN C C] = 16.22 kN C The members CJ and CF of the loaded truss cross but are not connected to members BI and DG. Compute the forces in members BC, C1, C1, and m 7‘ I HI. 5.00 kN T b \x _ 2i} =0 —’7 dx= [Moe GO° “liroblleifililfl “N Jr? 1’ {aid g 4 ,0 8 F F v ZMFWO 5657+ “3(0) + 4(01)~d7 OZ) + lysi‘nQOC myme (4) = O 4 law we: 2,: 6:53.? 2!? :0 cash/1&0 Hi7. "JC 3M6 =0 ‘ Jars-5:337 (Ml-dosiwo) :: 33.7 ZMI=O 4 Bc=3kN,C. zMgo iii/=0 ’37. H41 ’4.~I(o,25m9 +ICSEVLOL :63 5 [5.2442 +4+ IQZSMBBJ’] 1H (4) t.f4r(3'>7-I4,z(a>—;~(2§j +32 6) (5, 2 44.213) $601» 344) + 39.2 5114961330 =0 1! X f; )5 r (Hint. Use section iz—a.) 6.39 Determine the force in members”le and FH of the truss shown. Fig. P639 SSkN SSkN 35kN [email protected] =30m L " 7 [4'6 FAA WZero—%roLMW\\ws m» far It FR”; :0 k612Fw1=0 6"". FBE\(v \FBBZO . /= w, H H. MOonfiL-flcb =0} ...
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This note was uploaded on 11/21/2011 for the course ENGR 211 taught by Professor Cooper during the Winter '10 term at Cal Poly.

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211_5TrussProbs_solns - WW“... ‘1.“ . 4/11 A snOW...

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