lecture25

# lecture25 - Physics 2102 Jonathan Dowling Lecture 25...

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Lecture 25 Lecture 25 Physics 2102 Jonathan Dowling Optics: Images Optics: Images

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Thin Lenses Thin Lenses f i p 1 1 1 = + For small angles and thin lenses, Convergent: f positive Divergent: f negative ÷ - - = 2 1 1 1 ) 1 ( 1 r r n f Lens maker’s equation Convergent lens Divergent lens
Images due to lenses: An object placed beyond a convergent lenses’ focal point , will produce a real, inverted image on the other side of the lens. This is the principle used in projectors. An object placed between a convergent lens and its focal point will produce a virtual image on the same side as the object. Divergent lenses always produce a virtual image on the same side as the object. Real images have i positive in formulas, virtual images have i negative.

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Locating images by drawing rays: A ray of direction initially parallel to the axis will pass through the focal point. A ray that initially has a direction that passes through the focal point will emerge parallel to the central axis. A ray going through the center of the lens will be undeflected. The image of a point appears where all rays emanating from a point intersect.
Example Example An object 1.2cm high is placed 4cm from a bi-convex lens with r 1 =10cm and r 2 =15cm. Find the position and size of the image. A second lens of focal length +6cm is placed 12cm to the right of the first lens. Find the position and size of the new image.

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Images from Images from spherical mirrors spherical mirrors f i p 1 1 1 = + Consider an object placed between the focal
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## This note was uploaded on 11/18/2011 for the course PHYSICS 2102 taught by Professor Dowling during the Fall '10 term at LSU.

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lecture25 - Physics 2102 Jonathan Dowling Lecture 25...

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