{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Fluid mechanics report

# Fluid mechanics report - can be determined α z 1 = α z 2...

This preview shows pages 1–2. Sign up to view the full content.

The selection of the ideal pump is based upon the following assumptions: 1. That the pressure at P 1 and P 2 is a gage pressure, that is at atmospheric pressure, therefore indicating the P 1 and P 2 are equal to zero. 2. That the shaft rotation rate, n = 20 rad/s. 3. That rate of flow, Q = 6.309 m/s 4. Using the continuity theorem, that implies that the density is conserved. Using the energy equation, + α + z 1 = + α + z 2 – h p + h f + h turbine Using P 1 = 0 and P 2 = 0 (due to the assumption that gage pressure equals zero), v 1 = 0, v 2 = 0, and h turbine = 0 (since there is no turbine present), and h f = . Therefore, find h f h f = equation 1 However, we have to first determine the average velocity of the pipe, V. Using Q = VA Q = VA V = = = 3.459 10 -3 Using the value of V as obtained above, and substitute into equation 1. Therefore, h f = = = 1.647 10 -5 By substituting the value obtained from h f , it is substituted into the energy equation and h p can be

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: can be determined. + α + z 1 = + α + z 2 – h p + h f + h turbine 0 + 0 + 15.24 = 0 + 0 + 45.72 – h p + 1. 647 + 0 h p = 45.72 + 1.647 10-5 – 15.24 = 20.48 m To get C max , = 70 – 274500 Therefore, in order to find , (Q = 6.309 10-5 m 3 /s, shaft rotation, n = 20 rads-1 70 -274500 = 0 274500 C 2 = 70 C = ± 0.01597 whereby, C 0 = 0.01597 Ƞ max = 70 (0.01597) – 91500 (0.01597) 3 = 0.7452 Therefore, to find the head pressure ≈ 6.04 – 161 (0.01597) ≈ 3.4688 = ϕ = = 0.1478 C = Q = 0.01597 (20) (0.1478) 3 = 3.24 Efficiency: = whereby the power to water = mw s = γ Q h p = Therefore, using Ƞ max = 0.7452, 0.7452 = 0.7452 = Power input = 94.12 W Based on the dimensionless performance of the pump, and using 0 < C < 0.027 C = When C = 0, = 0 Therefore it is found that D p = invalid. When C = 0.027, = 0.027 D p = 0.124 m Whereby, D p 0.124 m...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern