Chapter_14_Solutions

Chapter_14_Solutions - Chapter 14 d 14-1 N 22 3.667 in P 6...

Info iconThis preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 14 14-1 22 3.667 in 6 N d P  Table 14-2: Y = 0 . 331 Eq. (13-34): (3.667)(1200) 1152 ft/min 12 12 dn V Eq. (14-4 b ): 1200 1152 1.96 1200 K v Eq. (13-35) : 15 33 000 33 000 429.7 lbf 1152 t H W V Eq. (14-7): 1.96(429.7)(6) 7633 psi 7.63 kpsi . 2(0.331) t KWP Ans FY v ________________________________________________________________________ 14-2 18 1.8 in 10 N d P  Table 14-2: Y = 0.309 Eq. (13-34): (1.8)(600) 282.7 ft/min 12 12 dn V Eq. (14-4 b ): 1200 282.7 1.236 1200 K v Eq. (13-35) : 2 33 000 33 000 233.5 lbf 282.7 t H W V Eq. (14-7): 1.236(233.5)(10) 9340 psi 9.34 kpsi . 1.0(0.309) t Ans FY v ________________________________________________________________________ 14-3 1.25(18) 22.5 mm dm N Table 14-2: Y = 0.309 3 (22.5)(10 )(1800) 2.121 m/s 60 60 dn V  Eq. (14-6 b ): 6.1 2.121 1.348 6.1 K v Eq. (13-36): 60 000 60 000(0.5) 0.2358 kN 235.8 N (22.5)(1800) t H W dn Eq. (14-8): 1.348(235.8) 68.6 MPa . 12(1.25)(0.309) t KW Ans FmY v ________________________________________________________________________ Chapter 14, Page 1/39
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
14-4 Y = 0.296 8(16) 128 mm dm N  Table 14-2: 3 (128)(10 )(150) 1.0053 m/s 60 60 dn V 6.1 1.0053 1.165 6.1 K v Eq. (14-6 b ): 60 000 60 000(6) 5.968 kN 5968 N (128)(150) t H W dn  Eq. (13-36): Eq. (14-8): 1.165(5968) 32.6 MPa . 90(8)(0.296) t KW Ans FmY v ________________________________________________________________________ 4-5 Y = 0.296 1 1(16) 16 mm N Table 14-2: 3 (16)(10 )(400) 0.335 m/s 60 60 dn V 6.1 0.335 1.055 6.1 K v Eq. (14-6 b ): 60 000 60 000(0.15) 0.4476 kN 447.6 N (16)(400) t H W dn Eq. (13-36): Eq. (14-8): 1.055(447.6) 10.6 mm 150(1)(0.296) t F mY v From Table 13-2, use F = 11 mm or 12 mm, depending on availability. Ans. _____ ___ 4-6 Y = 0.322 _ _______________________________________________________________ 1 2(20) 40 mm N Table 14-2: 3 (40)(10 )(200) 0.419 m/s 60 60 dn V 6.1 0.419 1.069 6.1 K v Eq. (14-6 b ): Eq. (13-36): 60 000 60 000(0.5) 1.194 kN 1194 N (40)(200) t H W dn Eq. (14-8): 1.069(1194) 26.4 mm 75(2.0)(0.322) t F mY v From Table 13-2, use F = 28 mm. Ans. _____ ________________________________ _ __________________________________ Chapter 14, Page 2/39
Background image of page 2
14-7 24 4.8 in 5 N d P  Table 14-2: Y = 0.337 (4.8)(50) 62.83 ft/min 12 12 dn V Eq. (13-34): Eq. (14-4 b ): 1200 62.83 1.052 1200 K v Eq. (13-35) : 6 33 000 33 000 3151 lbf 62.83 t H W V Eq. (14-7): 3 1.052(3151)(5) 2.46 in 20(10 )(0.337) t KWP F Y v Use F = 2 . 5 in Ans. _______________________________________________ 4-8 _________________________ 1 16 4.0 in 4 N d P  Table 14-2: Y = 0.296 (4.0)(400) 418.9 ft/min 12 12 dn V Eq. (13-34): Eq. (14-4 b ): 1200 418.9 1.349 1200 K v Eq. (13-35) : 20 33 000 33 000 1575.6 lbf 418.9 t H W V Eq. (14-7): 3 1.349(1575.6)(4) 2.39 in 12(10 )(0.296) t F Y v Use F = 2 . 5 in Ans. _______________________________________________ 4-9 Try P = 8 which gives d = 18 / 8 = 2 . 25 in and Y = 0 . 309 . Eq. (13-34): _________________________ 1 (2.25)(600) 353.4 ft/min 12 12 dn V 1200 353.4 1.295 1200 K v Eq. (14-4 b ): Eq. (13-35): 2.5 33 000 33 000 233.4 lbf 353.4 t H W V Eq. (14-7): 3 1.295(233.4)(8) 0.783 in 10(10 )(0.309) t F Y v Using coarse integer pitches from Table 13-2, the following table is formed. Chapter 14, Page 3/39
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
P d V K v W t F 2 9.000 1413.717 2.178 58.356 0.082 3 6. 0 942.478 1.785 87.535 0.152 1 1 10 1.800 12 1.500 00 4 4.500 706.858 1.589 16.713 0.240 6 3.000 471.239 1.393 75.069 0.473 8 2.250 353.429 1.295 233.426 0.782 282.743 1.236 291.782 1.167 235.619 1.196 350.139 1.627 16 1.125 176.715 1.147 466.852 2.773 Other considerat ta e G i re P = 8 ( F = 7 / 8 in) and P =10 ( F = 1 . 25 in) . Ans. _____ _____ ions may dic te the sel ction. ood cand dates a _ _____________________________________________________________ 14-10 Try m = 2 mm which gives d = 2(18) = 36 mm and Y = 0 . 309 . 3 (36)(10 )(900) 1.696 m/s dn V   60 60 Eq. (14-6 b ): 6.1 1.696 1.278 6.1 K v Eq. (13-36): 60 000 60 000(1.5) 0.884 kN 884 N (36)(900) t H W dn Eq. (14-8): 1.278(884) 24.4 mm 75(2)(0.309) F Using the prefer ed r module sizes from Table 13-2: W t F m d V K v 1.00 18.0 0.848 1.139 1768.388 86.917 1.25 22.5 1.060 1.174 1414.711 57.324 1 1 1 1 1 1 1.50 27.0 1.272 1.209 1178.926 40.987 2.00 36.0 1.696 1.278 884.194 24.382 3.00 54.0 2.545 1.417 589.463 12.015 4.00 72.0 3.393 1.556 442.097 7.422 5.00 90.0 4.241 1.695 353.678 5.174 6.00 08.0 5.089 1.834 294.731 3.888 8.00 44.0 6.786 2.112 221.049 2.519 0.00 180.0 8.482 2.391 176.839 1.824 2.00 216.0 0.179 2.669 147.366 1.414 16.00 288.0 3.572 3.225 110.524 0.961 20.00 360.0 16.965 3.781 88.419 0.721 25.00 450.0 21.206 4.476 70.736 0.547 32.00 576.0 27.143 5.450 55.262 0.406 40.00 720.0 33.929 6.562 44.210 0.313 50.00 900.0 42.412 7.953 35.368 0.243 Chapter 14, Page 4/39
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
1/2 3 2 3 1.204(202.6) 1 1 2 C  100 100(10 ) cos20 0.228 0.684 2100 1.204(202.6) 1 1 0.669 in 100(10 ) 0.228 0.684 F F          Use F = 0 . 75 in Ans.
Background image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 39

Chapter_14_Solutions - Chapter 14 d 14-1 N 22 3.667 in P 6...

This preview shows document pages 1 - 7. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online