Midterm Solutions

Midterm Solutions - ¯ X = $42 500 µ = 50 000 s = $20...

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Unformatted text preview: ¯ X = $42, 500 µ ￿= 50, 000 s = $20, 000 α = 0.10 H0 : µ = 50, 000 HA : µ ￿= 50, 000 t = = = x − µ0 ¯ √ s/ n 42500 − 50000 √ 20000/ 20 −1.677 0.10 < p − value < 0.20 p − value > α n ≥ ≥ ≥ 2 zα/2 0.25 E2 1.962 0.25 0.0252 1526.64 n = 200 p = 0. 7 ˆ p± ¯ 0.7 ± 0.7 ± ￿ zα / 2 ￿ 1.96 p(1 − p) ¯ ¯ n 0.7(0.3) 200 0.0635 (0.6335, 0.7635) ¯ nSF = 15; XSF = $1, 200; sSF = $200 ¯ nP A = 12; XP A = $1, 050; sP A = $175 H0 : HA : t µSF = µP A µSF ￿= µP A = = ¯ ¯ (XSF − XP A ) − 0 ￿2 sSF s2 A P nSF + nP A 1200 − 1050 ￿ 2002 1752 15 + 12 = df 2.08 = min 15 − 1, 12 − 1 = 11 0.025 < one tail < 0.05 0.05 < p − value < 0.10 α = 0.05 p − value > α H0 P layer 1 Online 10 Casino 8 Dif f erence −2 2 15 10 −5 3 −5 0 5 45 08 23 2 −5 6 4 −5 −9 α = 0.10 H0 : µd = 0 HA : µd ￿= 0 t = = = ¯ d − µd √ sd / n −2.625 − 0 √ 4.75/ 8 −1.56 0.05 < < 0.10 0.10 < α one tail p − value < 0.20 H0 7 −3 −10 −7 8 −2 −2 0 pD − pC ≤ 0 H0 : pD − pC > 0 HA : z = = = ￿ (¯D − pC ) − 0 p ¯ p(1 − p)( n1 + ¯ ¯D 1 nC ) (0.41667 − 0.36667) − 0 ￿ 1 1 0.392(0.608)( 300 + 300 ) 1.25 α = 0.05 p − value > α ...
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This note was uploaded on 11/20/2011 for the course PSTAT 5E taught by Professor Eduardomontoya during the Fall '08 term at UCSB.

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