Lecture 37_rev2 - Lecture 37 Op-amps in the s-domain Mutual...

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Lecture 37 Op-amps in the s-domain
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Mutual inductance: s-domain • Just like before: – Replace derivatives with “s” and initial conditions ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 - - - - + + + = + + + = + = + = 0 0 0 0 1 2 2 1 2 2 2 2 1 1 2 1 1 1 1 2 2 2 2 1 1 1 MI I L MI I L s V MI I L MI I L s V dt dI M dt dI L V dt dI M dt dI L V M + V1 - L1 L2 I 1 + V2 - I 2
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Op-amps with capacitors in s-domain • Inverting: – Overall gain = -Z F /Z 1 – Input resistance =Z 1 – V 1 =0 • Caps: replace Z with 1/sC Z F Z 1 V 1 V in V out - + Z F = R F Z 1 =1/sC V 1 V in V out - + • Example: Z 1 b C – Now gain = -sR F C – Zero at s=0 – s means acts as a differentiator: – V out =-R F C(dV in /dt)
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• Overall gain = -Z F /Z 1 • Compute Z 1 (s), Z F (s) • Find H(s) • One pole, one zero V 1 V in V out - + R1 RF CF C1 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 , 1 1 1 1 1 1 1 1 1 1 1 1 1 || C R z C R p C R s C C R s C C R s C C R s C Z Z s H C R
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Lecture 37_rev2 - Lecture 37 Op-amps in the s-domain Mutual...

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