Lectures 5+6_rev2

Lectures 5+6_rev2 - Lectures 5 6 Mesh/node with dep sources...

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Lectures 5+6 Mesh/node with dep sources Thevenin/Norton Power transfer
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Node-V/ mesh-I w/dep. sources ( 29 ( 29 2 1 1 1 2 1 1 0 I I r I I gm gmV r I R I r I I in o f in + = - = = + - - π π V1 V2 R F I in r π gmV1 r o 0 0 1 2 2 1 2 1 1 = - - - = - - - gmV r V R V V R V V r V I o f f in π I1 I2 Node voltage: two nodes 2 eq. Dep. Sources violate “same sign rule” Mesh current: only one real mesh for KVL: But add in KCL for dep. Source to get two Challenge: show these give same answer!
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A useful transformation R1 R2 R3 RC RB RA 1 3 1 3 2 2 1 1 R R R R R R R R R R R R R R A C B A C B + + = + + =
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Using this + V - + V - + V - + V - barb2right Y Y Collapse series
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Source transforms + = N Th N N R R R I I L Th Th R R V I + = I N R N R L V Th R Th R L + - I I N N Th Th N R I V R R = = Current divider: Series Resistance, Ohms Law: Norton Equivalent Thevenin Equivalent These are equivalent circuits if:
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Can model any linear 2-term network with Norton/Thevenin I N R N V Th R Th + - Norton Equivalent Thevenin Equivalent I N V Th Slope = 1/R Th =1/R N
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