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Unformatted text preview: hers3 \D \X 00...... T‘V”¢S\A‘$YV\Q{\. NR2 ( NO“ kw” TC) .ZQTDB. 1"]. “‘“V A .
$3M‘m‘ :3) tack $39006 3: \—\O\+ 0"” \H‘L‘fWA'k.’ S$m¥o\ Raf; = :L‘: b'ﬂ‘ (031. :1: bebo‘ rake (Q«\‘M’s nxqmguy = J1: Channel Parameters
N_RZ ' 1L2 Symbol ./ 111 0 ‘T4 Symbol Period = T
Symbol Rate =1/T  Bit rate, R
 Defines the number of b_it§ transmitted per second
 Aka. data rate
 Example: W  Audio system with 8—bit sampler (8 bit A/D) and signal sampling rate
of 8 kg ) R= 8*8000= 64 kbits/sec  Symbol (aka. Baud) rate, 1/T
 Defines the number of symbols transmitted per second  R= @aud ratex n (# of bits per symbol)
 If one bit is transmitted per symbol % R= Baud rate = 1/T Spring, 09 4 Léx————‘§‘g’g§$ig":€ @@ Binary vs. Mary Signaling I 9‘25” _ Binary MEL! Symbol 00 11 10 oo 01 oo :2) “:2 M) : .( v(t) Symbol .
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: . 4T} 4T}  Binary: Symbol has 2 allowed states (i.e. level), ex. 1 or O
 n (# of bits persymbol)=1  Magy: Each symbol has m finite states
 n (# of bits per symbol)= log2 m  EX. : 1 bit/symbol (binary) 9 m = 2 (Le. 0 or 1)
. EX.: 3 bits/symbol 9m = 8 (Le. 0, 1, 2, 3, 4, 5, 6, or 7) R = Baud rate x®
= (an) 5 mm AAAAAAAAAA Spring, 09 (E and V0 \A'HA 'ﬁ‘US‘NVt O'Q S um ‘Q \(Kuhey Y\
— Em) [\E = W
p—d E = n + S‘5Wbo\ RA“? ..
E —
”—— ‘ :—'> ‘OPS/ JAZ @D Example  The GSM standard specifies a data rate of 270.83 kbps,
SNRmin ofgaclB and B of 200 kHz. ”‘3‘"  Compare the actual capacity to maximum capacity C: B toszuausw) ; zoogg \bcngvr t0 permlR 2 ”no ~23 J, qZ‘I.
Q 6’39... ii?) 2 £32 HOPE  If SNR increased to 20 dB, calculate the channel capacity L— ZOOé'; K°°31K\’<‘ \00) ’3 \23 Mb?$‘ ’— ArC/Ei Q g 207. C. ’_ N27g \vxcm
Nola: 11710 dg \“Cm \“ $NQ‘" 0079’“; \KA Q. Spring, 09 3 £lettto$ciene AAAAAAAAAA D “bd‘A $ﬁ§m s‘ . 5E? ,15 P‘CT‘QWAkkmQ}(LQ 7:) @ QW'LV‘ EXQNO Eb é imrﬁb Qex YDF‘Y 2 E
No 9:. Moi“. A ' m3
WMr (haB3 __._ NodB k_\:pu( MSMI'HZ Q) Hz.
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 Fall '11
 Khalil

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