# Sol1A3 - ACTSC231 SOLUTION OF ASSIGNMENT 3 problems in text...

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ACTSC231 SOLUTION OF ASSIGNMENT 3 problems in text book: page 236 (1) 5.2.2, 5.2.4, 5.2.6 (2) 5.3.2, 5.3.4, (3) 5.4.2, 5.4.4, 5.4.6 (4) chapter 5 Review: 2,4,6,8 Solution 5.2.2 : P 82 = L × v 30 × 12 - 82+1 = L × v 279 = 259 . 34 , P 56 = L × v 30 × 12 - 56+1 = L × v 305 = 230 . 19 , solve v and L : v = 0 . 99542454 , L = 932 . 269561 and I 133 = L × (1 - v 30 × 12 - 133+1 = 604 . 594071 , Solution 5.2.4 B 0 = 117 , 134 . 80 , L = 988 . 45 , i (12) = 6% , j = i (12) / 12 = 0 . 005 so B 60 = 117 , 134 . 80 × (1 + j ) 60 - 988 . 45 s 60 | 0 . 005 = 89 , 033 . 10619 at time of 84-th payment, the balance is 89 , 033 . 10619 × (1 + 0 . 075 / 12) 84 - 60 - 988 . 45 s 84 - 60 | 0 . 00625 = 77 , 884 . 78032 at time of 83-th payment,the balance is 89 , 033 . 10619 × (1 + 0 . 075 / 12) 83 - 60 - 988 . 45 s 83 - 60 | 0 . 00625 = 78 , 383 . 334448 the interest paid for 84 payment is I 84 = 78 , 383 . 334448 × 0 . 00625 = 489 . 8958405 the last payment is 89 , 033 . 10619 × (1 + 0 . 075 / 12) 180 - 60 - 988 . 45

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## This note was uploaded on 11/21/2011 for the course MATH ACTSC 231 taught by Professor Zhou during the Spring '10 term at Waterloo.

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Sol1A3 - ACTSC231 SOLUTION OF ASSIGNMENT 3 problems in text...

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